44. A rescue helicopter is hovering over a person whose boat has sunk. One of the rescuers throws a life preserver straight down
1 answer:
Answer:
18.4 m
Explanation:
(a)
The known variables in this problem are:
u = 1.40 m/s is the initial vertical velocity (we take downward direction as positive direction)
t = 1.8 s is the duration of the fall
a = g = 9.8 m/s^2 is the acceleration due to gravity
(b)
The vertical distance covered by the life preserver is given by
If we substitute all the values listed in part (a), we find
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It depends on both of them.
In fact, the projectile begins its motion with an initial velocity of
and an angle of 
. On the y-axis (vertical direction), it is an accelerated motion with acceleration equal to -g (gravitational acceleration). The vertical velocity of the projectile at any time t is given by
and as it can be seen, this depends on both initial velocity and angle.
In fact, the projectile begins its motion with an initial velocity of
and as it can be seen, this depends on both initial velocity and angle.