The sentence is accurate, therefore TRUE is the answer.
Answer:
Distance of Earth from the Sun has nothing to do with the seasons only the tilt is responsible for the change in seasons.
Explanation:
The Earth's tilt does cause the seasons but the distance from the sun and has nothing to do with the change in seasons. In June, when the Northern Hemisphere is tilted in the direction of the Sun during the Northern Hemisphere summer the Earth is actually farthest from the Sun. In January, when the Southern Hemisphere is tilted in the direction of the Sun during the Northern Hemisphere winter the Earth is actually closest to the Sun. This is caused due to the elliptical orbit of the Earth. So, distance of Earth from the Sun has nothing to do with the seasons.
Answer:
8954000 J
Explanation:
The formula to find kinetic energy is:
<em>Kinetic energy = </em>
<em> × mass × (velocity)²</em>
So, Kinetic energy = × 370 × (220)²
Kinetic energy = 8954000 J
Answer:
4.8967m
Explanation:
Given the following data;
M = 0.2kg
∆p = 0.58kgm/s
S(i) = 2.25m
Ratio h/w = 12/75
Firstly, we use conservation of momentum to find the velocity
Therefore, ∆p = MV
0.58kgm/s = 0.2V
V = 0.58/2
V = 2.9m/s
Then, we can use the conservation of energy to solve for maximum height the car can go
E(i) = E(f)
1/2mV² = mgh
Mass cancels out
1/2V² = gh
h = 1/2V²/g = V²/2g
h = (2.9)²/2(9.8)
h = 8.41/19.6 = 0.429m
Since we have gotten the heigh, the next thing is to solve for actual slant of the ramp and initial displacement using similar triangles.
h/w = 0.429/x
X = 0.429×75/12
X = 2.6815
Therefore, by Pythagoreans rule
S(ramp) = √2.68125²+0.429²
S(ramp) = 2.64671
Finally, S(t) = S(ramp) + S(i)
= 2.64671+2.25
= 4.8967m
Answer:
The the angle between the axis of polarization of the light and the transmission axis of the analyzer is 52⁰.
Explanation:
Given;
I₀ as incident light intensity
The intensity of a linearly polarized light passing through a polarizer is given by Malus' law:
I = I₀Cos²θ
where;
I is the intensity after passing through the analyzer
θ is the the angle between the axis of polarization of the light and the transmission axis of the analyzer.
If 38% of the total intensity is transmitted, then I = 38% of I₀ = 0.38I₀
0.38I₀ = I₀Cos²θ
0.38 = Cos²θ
Cosθ = √0.38
Cosθ = 0.6164
θ = Cos⁻¹ (0.6164)
θ = 51.95° = 52⁰
Therefore, the angle between the axis of polarization of the light and the transmission axis of the analyzer to allow 38% of the total intensity to be transmitted is 52⁰.
