Question: 18 kilogram Mass Block rest on level surface if the coefficient of static friction between the Block and the surface is 0.6 what horizontal force is required to just move the blcok ( take gravity as 10m/s2
)
Answer:
108 N
Explanation:
From the question,
Applying
F' = mgμ................ Equation 1
Where F' = Frictional force = horizontal force required to just move the block, m = mass of the block, g = acceleration due to gravity, μ = coefficient of static friction.
From the question,
Given: m = 18 kg, μ = 0.6, g = 10 m/s²
Substitute these values into equation 1
F' = 18×0.6×10
F' = 108 N
Answer:
t=0.47s
Explanation:
the ball has uniformly accelerated movement due to gravity
Vo=initial speed=4.6m/s
g=gravity=-9.8m/s^2
Vf=final speed=0, the player must wait for the ball to stop. so the final speed will be 0
we can use the following ecuation
T=(Vf-Vo)/g
T=(0-4.6)/-9.8m/s^2
T=0.47s
Answer:
The length of the rope must be an integral multiple of the wavelength of the wave.
Explanation:
Answer:
B. There are no forces acting on the ball.
Explanation:
There are no forces acting on the ball.
The answer is A. Bob (<span>object's length)
</span>
