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algol13
3 years ago
6

A right rectangular prism has base dimensions of 3 inches by 12 inches and a height of 5 inches. An oblique rectangular prism ha

s base dimensions of 4 inches by 9 inches and a height of 5 inches. Are the volumes the same?
Mathematics
1 answer:
KonstantinChe [14]3 years ago
8 0
Yes they are. Given that a volume of a rectangular prism is V=l•w•h, we can plug them into an equation and compare them. I'll call the Right rectangular prism figure R and the oblique rectangular prism O


For Figure R, We know all the basic needs to find the volume. This means we can plug it in.

V=l•w•h
V=12•3•5
Now We can solve for V
V=12•15
V=180

The volume of the right rectangular prism is 180in^3


Now, For figure O.
V=9•4•5
V=9•20
V= 180.


With this in mind, We now can say that the volumes of both the rectangular prisms are the same.
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Solve x2 + 14x = −24 by completing the square.
Aleks04 [339]

Option A

The solution set of the equation is {-12, -2}

<h3><u>Solution:</u></h3>

Given equation is:

x^2 + 14x = -24

We have to find the solution set of this equation by completing the square

First, rearrange the equation so that only zero will be on the right side:

x^2 + 14x + 24 = 0 ----- eqn 1

<em><u>The general form of quadratic equation is:</u></em>

ax^2 + bx + c = 0 where a \neq 0

On comparing the given eqn 1 with general quadratic equation, we get

a = 1

b = 14

c = 24

In completing the square, we take half of coefficient of middle term "x" and then square it. Then we add it on both sides of the equation

So to complete the square, add (\frac{b}{2})^2 to both sides of the equation

x^2 + 14x + 24 + (\frac{14}{2})^2 = (\frac{14}{2})^2

x^2 + 14x + 24 + 7^2 = 7^2\\\\x^2 + 14x + 24 + 49 = 49

x^2 + 14x + 24 + 49 = 49\\\\x^2 + 14x + 49 = 49 - 24\\\\x^2 + 14x + 49 = 25\\\\(x + 7)(x + 7) = 25\\\\(x + 7)^2 = 25

Take square root on both sides

x + 7 = \sqrt{25}

x+7=\pm 5

Now make two equations

x + 7 = + 5 and x + 7 = -5

x = +5 - 7 = -2

x = -2

And,

x + 7 = -5

x = -5 - 7 = -12

x = -12

Therefore, the solution set of the equation is {-12, -2} and option A is correct

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3 years ago
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