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arsen [322]
3 years ago
6

You carry out a titration of a pure weak triprotic acid and only see two major pH jumps. One at 10.0 mL and the second one at 15

.0 mL. At what volume is the other equivalence point?
Chemistry
1 answer:
mafiozo [28]3 years ago
3 0
23 would be most likely
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Consider the unbalanced equation for the oxidation of butene. C4H8 + 6O2 Right arrow. CO2 + H2O For each molecule of C4H8 that r
antiseptic1488 [7]
Answer is C4H8 + 6O2 —> 4CO2 + 4H2O
4 0
3 years ago
Why does the same side of the moon always face earth? A. The rotational period of earth is the same as that of the moon B. The r
mixer [17]

Answer: A. the rotational period of the earth is the same as that of the moon

3 0
3 years ago
Read 2 more answers
1. Analysis of an unknown substance formerly used in rocket fuel reveals a composition of 93.28% nitrogen and 6.72% hydrogen by
Nitella [24]

Answer:

The formula of the compound is:

N2H2

Explanation:

Data obtained from the question:

Nitrogen (N) = 93.28%

Hydrogen (H) = 6.72%

Next, we shall determine the empirical formula for the unknown compound. This is illustrated below:

N = 93.28%

H = 6.72%

Divide by their molar mass

N = 93.28 /14 = 6.663

H = 6.72 /1 = 6.7

Divide by the smallest

N = 6.663 / 6.663 = 1

H = 6.72 /6.663 = 1

Therefore, the empirical formula is NH.

Now, we can obtain the formula of the compound as follow:

The formula of a compound is simply a multiple of the empirical formula.

[NH]n = 30.04

[14 + 1]n = 30.04

15n = 30.04

Divide both side by 15

n = 30.04/15

n = 2

Therefore, the formula of the compound is:

[NH]n => [NH]2 => N2H2

6 0
3 years ago
Can someone answer 4 for me please?
Mice21 [21]
I can’t see the whole question......
4 0
3 years ago
If the pressure inside your ballon is 800mmHG ,and the gas is at body temperature,37 degree Celsius , calculate the number of gr
SpyIntel [72]
With all of the information given (pressure, volume, temperature, and the molar mass), we need a formula that relates this all together. The formula we need is the ideal gas law, PV=nRT. Since the pressure is defined in millimeters of mercury, we need the R value that correlates with this, which is 62.4; on top of this, we need the temperature in Kelvin - simply add 273.15 to convert from Celsius. With all of this information, simply plug-and-chug:

PV=nRT
(800)(3.7) = n(62.4)(37 + 273.15)
n = 0.1529 moles

Finally, the problem is asking the amount of air in grams. We have moles, so all we need to do is multiply that value by the molar mass.

0.1529 moles x 29 grams per mole =
4.435 grams of air

The balloon has 4.435 grams of air inside it.

Hope this helps!
6 0
3 years ago
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