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pishuonlain [190]
3 years ago
6

You push a 2.0 kg block against a horizontal spring, compressing the spring by 14 cm. then you release the block, and the spring

sends it sliding across a tabletop. it stops 84 cm from where you released it. the spring constant is 290 n/m. what is the coefficient of kinetic friction between the block and the table?
Physics
1 answer:
Olin [163]3 years ago
8 0
The potential energy in the spring is given by:
V = \frac{1}{2} kx^2
where k is the spring constant and x is the compression of the spring.

The work done by friction is given by:
W = \int\limits {\overrightarrow F \cdot} \,\overrightarrow{ds} = F_{friction} s = \mu Ns = \mu mgs
where s is the sliding distance, N the normal force N = mg, m is the mass of the block, g is the gravitational acceleration and μ is the coefficient of dynamic friction.

The work done by friction must be equal to the energy provided by the spring:
\frac{1}{2} kx^2 = \mu mgs \\ \mu =  \frac{kx^2}{2mgs}
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An airplane has a takeoff speed of 62 m/s. assuming a constant acceleration of 1.7 m/s2, what is the minimum length of runway it
UkoKoshka [18]

Data:

u=0 m/s is the initial velocity of the plane

v=62 m/s is the final velocity of the plane (at which the plane takes off)

a=1.7 m/s^2 is the acceleration of the plane

To find the minimum distance S the plane needs to take off, we can use the following equation:

2aS=v^2 -u^2

Re-arranging it and substituting the numbers, we find

S=\frac{v^2-u^2}{2a}=\frac{(62 m/s)^2-0}{2(1.7 m/s^2)}=1131 m

3 0
3 years ago
Why do you lurch forward in a bus that suddenly slows? why do you lurch backward when it picks up speed? what law applies here?
AveGali [126]
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This law states that: A body will retain its state of rest or motion unless acted upon by an external force.

If you are moving and the bus suddenly stops, your body will lurch forward trying to retain its state of motion until it comes to rest and changes its state by the external force acted on it.

If you are at rest and the bus suddenly moves, your body will lurch backwards trying to retain its state of rest and opposing the force of motion until it is forced to change its state by this force.
8 0
3 years ago
A 60 kg man jumps down from a 0.8 m table. What is the speed when he
Rom4ik [11]

Answer: Speed = 4 m/s

Explanation:

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Mass M = 60 kg

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Before the man jumps, he will be experiencing potential energy at the top of the table.

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Substitute all the parameters into the formula

P.E = 60 × 9.8 × 0.8

P.E = 470.4 J

As he jumped from the table and hit the ground, the whole P.E will be converted to kinetic energy according to conservative of energy.

When hitting the ground,

K.E = P.E

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Substitute m and 470.4 into the formula

470.4 = 1/2 × 60 × V^2

V^2 = 470.4/30

V^2 = 15.68

V = square root (15.68)

V = 3.959 m/s

Therefore, the speed of the man when hitting the ground is approximately 4 m/s

4 0
3 years ago
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