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SOVA2 [1]
3 years ago
7

What variables can be used to determine the pressure exerted by a gas?

Chemistry
1 answer:
Molodets [167]3 years ago
3 0
Pressure = force/area
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Metals have low ionization energies and readily share their ________ or outer electrons with each other to form an electron ____
Dmitry [639]

Explanation:

Metals are the species which readily lose electrons in order to attain stability. This electron lost by the atom is actually present in its outermost shell which is also known as valence shell.

Ionization energy is defined as the energy required to remove the most loosely bound electron from a neutral gaseous atom.

When we move across a period from left to right then there occurs a decrease in atomic size of the atoms. Therefore, ionization energy increases along a period.  

But when we move down a group then there occurs an increase in atomic size of the atoms due to addition of number of electrons in the atoms. Hence, ionization energy decreases along a group.

Thus, we can conclude that metals have low ionization energies and readily share their valence or outer electrons with each other to form an electron sea. These electrons are delocalized or shared among all the atoms that are bonded together and can therefore move freely throughout the metal structure.

3 0
4 years ago
Read 2 more answers
1. What are commonly called as "shooting stars"?
nydimaria [60]

Answer:

B

B

A

C

D

Explanation:

I think dont take my word for though

6 0
3 years ago
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Na3(PO4) + HCl yields NaCl + H3(PO4)​
oksano4ka [1.4K]

Chemical Equation Balancer

7 0
3 years ago
Of the following forms of carbon dioxide, which has the lowest entropy?
saw5 [17]
Those atoms which have same atomic numbers but different atomic misses are lowest entropy.
4 0
3 years ago
The electron in a hydrogen atom can undergo a transition from n = 4 to n = 3, emitting a photon with energy 1.06 × 10 –19J. Use
konstantin123 [22]

Answer:

Wavelength (λ) = 1.875 × 10⁻⁶ m

Explanation:

Given:

Energy (e) =  1.06 × 10⁻¹⁹ J

Find:

Wavelength (λ) = ?

Computation:

e = hc / λ

λ = hc / e

where c = 3 × 10⁸

Planck's constant (h) = 6.625 × 10⁻³⁴

So,

Wavelength (λ) = (6.625 × 10⁻³⁴)(3 × 10⁸) / (1.06 × 10⁻¹⁹)

1. Wavelength (λ) = 1.875 × 10⁻⁶ m

2. Given n = 4 to n = 3 both are integer not fraction so, electron is quantize

5 0
3 years ago
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