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sergiy2304 [10]
3 years ago
12

A rocket has landed on Planet X, which has half the radius of Earth. An astronaut onboard the rocket weighs twice as much on Pla

net X as on Earth. If the escape velocity for the rocket taking off from Earth is v0 , then its escape velocity on Planet X is:
Physics
1 answer:
Burka [1]3 years ago
7 0

Explanation:

Let acceleration due to Gravity for a planet is given by:

g_X=GM/R^2

Here,g_X = 2g

Escape velocity is given by:

v =\sqrt{ \frac{2GM} {R}} = \sqrt{2aR}

Here, R=R_earth/2

and g_X = 2g

Therefore,v=\sqrt(2(2g)(R/2))=v_0

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Depict the following path: You drive 14 blocks East, 7 blocks North, and 2 blocks West. Use the vertex of the graph (coordinates
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Answer:

Displacement = 12\hat{i} +7\hat{j}

Magnitude of displacement = 13.89 units

Angle of displacement = 30.26°

Explanation:

Mark the co-ordinates of each of the end points of the vectors.

The marked co-ordinates are shown below.

Displacement is the shortest distance between two points. Here, displacement between the starting and end points is the vector \overrightarrow{OA}.

Displacement vector for a point A(x,y) from origin O is given as:

\overrightarrow{OA}=(x-0)\hat{i}+(y-0)\hat{j}

Magnitude is given as:

|\overrightarrow{OA}|=\sqrt{x^{2}+y^{2}}

Direction of the vector is given as:

\theta=tan^{-1}\frac{y}{x}

Therefore, displacement vector is:

\overrightarrow{OA}=(12-0)\hat{i}+(7-0)\hat{j}\\ \overrightarrow{OA}=12\hat{i}+7\hat{j}

Magnitude of displacement is given as:

|\overrightarrow{OA}|=\sqrt{x^{2}+y^{2}}\\ |\overrightarrow{OA}|=\sqrt{12^{2}+7^{2}}\\ |\overrightarrow{OA}|=\sqrt{144+49}\\\\ |\overrightarrow{OA}|=13.89

Angle of displacement is:

tan\theta=\frac{y}{x} =\frac{7}{12}\\\theta=tan^{-1}(\frac{7}{12})

\theta=30.26°

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4 years ago
You have a friend who reports that he falls asleep easily around 11 PM but then awakens for about an hour most nights around two
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Answer:

can I have more details please, Thanks!

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what is light ?

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When all the spheres on earth interact, that is known as _______
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