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Ann [662]
3 years ago
6

In 1825, French scientist François-Vincent Raspail became the first scientist to observe that every cell is produced through cel

l division. How is cell division different in single-celled organisms than in multi-celled organisms? A. Single-celled organisms duplicate their genetic material twice during cell division. B. Cytokinesis divides single-celled organisms into three daughter cells. C. There is no metaphase for single-celled organisms. D. Cell division results in reproduction in single-celled organisms.
Physics
2 answers:
Aleonysh [2.5K]3 years ago
8 0

Answer:  A.

Single-celled organisms duplicate their genetic material twice during cell division

Explanation:

All multicellular organisms use cell division for growth and the maintenance and repair of cells and tissues. Single-celled organisms use cell division as their method of reproduction. Somatic cells contain two copies of each of their chromosomes (one copy from each parent).

Nuetrik [128]3 years ago
6 0

Answer:

Cell division results in reproduction in single-celled organisms. The correct option is D.

Explanation:

Single celled organism which are equally known as unicellular organisms are organisms which are made up of one cell. Due to the simplicity of the structure of these organisms, reproduction can be achieved through cell division.

Multicellular organisms as the name implies is made up of multiple cells,unlike unicellular organisms, which are to varying degrees integrated and independent.

Every cell is produced through cell division.

Cell division results to reproduction in single-celled organisms while cell division aids in the formation of gametes, which are cells that combine with others to form sexually produced offspring. It is also responsible for the development of a multi-celled organism from a single fertilised egg cell.

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A gas is compressed at constant temperature from a volume of 5.68 L to a volume of 2.35 L by an external pressure of 732 torr. C
Vlada [557]

Answer: The work done in J is 324

Explanation:

To calculate the amount of work done for an isothermal process is given by the equation:

W=-P\Delta V=-P(V_2-V_1)

W = amount of work done = ?

P = pressure = 732 torr = 0.96 atm    (760torr =1atm)

V_1 = initial volume = 5.68 L

V_2 = final volume = 2.35  L

Putting values in above equation, we get:

W=-0.96atm\times (2.35-5.68)L=3.20L.atm

To convert this into joules, we use the conversion factor:

1L.atm=101.33J

So, 3.20L.atm=3.20\times 101.3=324J

The positive sign indicates the work is done on the system

Hence, the work done for the given process is 324 J

5 0
3 years ago
While rowing in a race, John uses his arms to exert a force of 155 N per stroke
Basile [38]

Answer:

Workdone = 2906.25J

Explanation:

Given the following data;

Force, F = 155

Distance, d = 0.75

Stroke, s = 25

Mathematically, work done is given by the formula;

Work done = force * distance * stroke

W = F * d * s

Where,

W is the work done

F represents the force acting on a body.

d represents the distance covered by the body.

s is the number of strokes.

Substituting into the equation, we have;

Workdone = 155*0.75*25

Workdone = 2906.25J

6 0
3 years ago
Write two functions of kotokis​
Annette [7]

Answer:

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6 0
3 years ago
Obtain the zeroes of polynomial
morpeh [17]

I assume you meant to say

f(x)=2x^4+3x^3-5x^2-9x-3

Given that <em>x</em> = √3 and <em>x</em> = -√3 are roots of <em>f(x)</em>, this means that both <em>x</em> - √3 and <em>x</em> + √3, and hence their product <em>x</em> ² - 3, divides <em>f(x)</em> exactly and leaves no remainder.

Carry out the division:

\dfrac{2x^4+3x^3-5x^2-9x-3}{x^2-3} = 2x^2+3x+1

To compute the quotient:

* 2<em>x</em> ⁴ = 2<em>x</em> ² • <em>x</em> ², and 2<em>x</em> ² (<em>x</em> ² - 3) = 2<em>x</em> ⁴ - 6<em>x</em> ²

Subtract this from the numerator to get a first remainder of

(2<em>x</em> ⁴ + 3<em>x</em> ³ - 5<em>x</em> ² - 9<em>x</em> - 3) - (2<em>x</em> ⁴ - 6<em>x</em> ²) = 3<em>x</em> ³ + <em>x</em> ² - 9<em>x</em> - 3

* 3<em>x</em> ³ = 3<em>x</em> • <em>x</em> ², and 3<em>x</em> (<em>x</em> ² - 3) = 3<em>x</em> ³ - 9<em>x</em>

Subtract this from the remainder to get a new remainder of

(3<em>x</em> ³ + <em>x</em> ² - 9<em>x</em> - 3) - (3<em>x</em> ³ - 9<em>x</em>) = <em>x</em> ² - 3

This last remainder is exactly divisible by <em>x</em> ² - 3, so we're left with 1. Putting everything together gives us the quotient,

2<em>x </em>² + 3<em>x</em> + 1

Factoring this result is easy:

2<em>x</em> ² + 3<em>x</em> + 1 = (2<em>x</em> + 1) (<em>x</em> + 1)

which has roots at <em>x</em> = -1/2 and <em>x</em> = -1, and these re the remaining zeroes of <em>f(x)</em>.

3 0
3 years ago
You have four identical conducting spheres: A, B, C, and D. In each scenario below, sphere A starts with a charge of -Q, sphere
mash [69]

Answer:

1)    Q_c = - ½ Q ,  2)   Q_c = + ¼ Q , 3)    Q_c= 3/8 Q

Explanation:

For this exercise we must use that equal charges repel and charges with different signs attract. When two objects are in contact, the charges are evenly distributed between them.

Scenario 1.

when the two spheres touch the charge -Q is distributed between them, when separating each sphere has a charge = -1/2 Q

as there are no more interacts sphere C its charge is

         Q_c = - ½ Q

Scenario 2

when the two spheres touch the charge -Q is distributed between them, when separating each one has a charge

        Q_a = Q_d = - ½ Q

now the sphere D and C touch the charge is Q_net = -1/2 Q + Q = + ½ Q

when separating each sphere has half the charge

            Q_d = Q_c = + ¼ Q

since sphere C has no more interaction, its charge is

           Q_c = + ¼ Q

Scenario 3

A and B touch the net charge is Q_net = - Q + 0 = - Q

when parting

          Q_a = Q_b = - ½ Q

now B and D touch, the charge is Q_net = - ½ Q +0 = - ½ Q

when parting

           Q_b = Q_d = - ¼ Q

finally C and D touch

the net charge is Q_net = Q- ¼ Q = ¾ Q

when separating each one is left with half the load

           Q_c = Q_d = 3/8 Q

          Q_c= 3/8 Q

8 0
3 years ago
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