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4 years ago

What must be part of a quantitative observation?

Physics

2 answers:

inna [77]4 years ago

8 0

a number hope this helps

Pani-rosa [81]4 years ago

5 0

Answer with Explanation:

There are two types of Observation:

1.→ Qualitative Observation : In which things are Selected on the basis of Quality ,like Color,Shape , Size ,Behavior,Nature of a person, etc...

2.→Quantitative Observation: Representation is done with the help of numbers ,Alphabets or Special Characters or by Combining all of them.

Option A: A Change of State: ------It denotes Quality.

Option B: A change in Size : ----It can be both Quality as well as Quantity.For Example Animal loosing and gaining weight can be represented in terms of both numbers as well Quality.For example :50-30,Fat-Thin.

Option C: A number-----It denotes Quantity.

Option D: A Color----It denotes Quality.

⇒A Number is : is must a quantitative observation.

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What is the magnitude of the net torque on the pulley about the axle?

jeyben [28]

Answer: Torque= tangential force × radius of the pulley

Explanation:

Pulley is a simple machine which helps us to lift loads by applying the force in a convenient direction. It consists of a grooved wheel which is free to rotate about an axle passing through the center of the pulley.

For a pulley, the torque $T=$ tangential force × radius of the pulley

Pulleys can be used in combination also to achieve a desired output.

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4 years ago

The table represents the speed of a car in a northern

Sidana [21]

Answer:

O Column 1 should be titled "Time," and Column 2 shouldbe titled "Velocity,"

O Column 1 should be titled "Velocity," and Column 2 should be titled "Time."

O Column 1 should be titled "Time," and Column 2 should be titled "Acceleration."

O Column 1 should be titled "Acceleration," and Column 2 should be titled "Time."

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3 years ago

A billiard ball with a mass of 0.15 kg has a velocity of 5 m/s. It strikes the bumper of the table perpendicularly and bounces s

Marianna [84]

Initial momentum = 0.15 kg * (-5 m/s) = - 0.75 N*s

final momentum = 0.15 * ( 3 m/s) = 0.45 N*s

Change in momentum = final momentum - initial momentun =

= 0.45N*s - (- 0.75N*s) = 1.2 N*s

Answer: 1.2 N*s

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3 years ago

26. A 40 kg boy jumps from a height of 4m onto a plate-form mounted on springs. As the

denpristay [2]

Answer:

c. 1600J

Explanation:

The loss in potential energy of the boy is given by:

$U=mg \Delta h$

where

m = 40 kg is the mass of the boy

g = 9.8 m/s^2 is the acceleration of gravity

$\Delta h = 4 m + 0.02 m = 4.02 m$ is the total change in the height of the boy (4 metres + 2 cm due to the compression of the spring)

Substituting, we find

$\Delta U = (40 kg)(9.8 m/s^2)(4.02 m) = 1577 J \sim 1600 J$

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3 years ago

Complete the electron-pushing mechanism for the e1 reaction when 2-methylbutan-2-ol is treated with 20% sulfuric acid.

Sav [38]

E1 reaction works in the mechanism that the removal of an HX substituent results in the formation of a double bond. The E1 reaction for 2-methylbutan-2-ol is shown in the figure. This reaction is called acid-catalyzed dehydration of a tertiary alcohol.

The mechanism works in three major steps:
1. The OH group of the main reactant is hydrated by H2SO4 so it becomes H2O.
2. The H2O leaves taking electrons with it. This results to a carbocation intermediate on the carbon atom where it was attached.
3. Another H2O protonates the beta carbon. This is the carbon atom next to the carbocation. It will donate its electrons to the neighboring C-C bond, as indicated by the arrow. The carbons are rehybridized from sp3 to sp2, which is a pi bond. As a result, a double bond forms.

The product is 2-methyl-2-butene.

6 0

4 years ago

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