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cupoosta [38]
3 years ago
13

Will mark brainlist THANKS!

Physics
1 answer:
VLD [36.1K]3 years ago
3 0

Answer:

a) 0=10

b)20

Explanation:

b) Mass of the object (m)= 10kg

Acceleration of the object (a)= 2m/s^2

Force acting on the object (F)= ?

Solution

F = m × a

F = 10 × 2

F= 20N

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The hydraulic oil in a car lift has a density of 8.53 x 102 kg/m3. The weight of the input piston is negligible. The radii of th
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Answer:

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(b) the input force is 37.49 N

Explanation:

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P is pressure

F is force

A is circular area = πr²

\frac{F_1}{A_1} =\frac{F_2}{A_2} \\\\F_2 = \frac{F_1*A_2}{A_1} =\frac{F_1* \pi r_2^2}{\pi r_1^2} = \frac{F_1*  r_2^2}{ r_1^2} \\\\F_2 = \frac{22600*(5.43*10^{-3})^2 }{(0.135)^2}\\\\F_2 = 36.56 \ N

Part (b) The input force needed to support 22600-N weight, when the  bottom surface of the output plunger is 1.20 m above that of the input plunger

P_2 = P_1 + \rho gh

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F_2 = F_1(\frac{A_2}{A_1} ) + \rho gh*A_2\\\\F_2 = F_1(\frac{r_2^2}{r_1^2} )+\rho gh(\pi r_2^2)\\\\F_2 = 22600(\frac{5.43*10^{-3}}{0.135})^2 \ + 853*9.8*1.2*\pi (5.43*10^{-3})^2\\\\F_2=36.56 + 0.93\\\\F_2 = 37.49 \ N

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Explanation:

I know

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