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3 years ago

Will mark brainlist THANKS!

Physics

1 answer:

VLD [36.1K]3 years ago

3 0

Answer:

a) 0=10

b)20

Explanation:

b) Mass of the object (m)= 10kg

Acceleration of the object (a)= 2m/s^2

Force acting on the object (F)= ?

Solution

F = m × a

F = 10 × 2

F= 20N

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Select the correct answer. A ball is thrown straight down from the top of a building at a velocity of 16 ft/s. The building is 4

BartSMP [9]

Answer:

The ball takes 5s to reach the ground

Explanation:

in order to solve this problem we use the kinematics equation with gravity as acceleration:

$h=v_0t+1/2*gt^2$

we replace the values

$0=1/2*32t^2+16t-480$

We solve this quadratic equation:

t=5s

t=-6s (this solution has not physical sense)

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3 years ago

What is the velocity of 360?

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Answer:

3/360 is 120. your velocity is 120

Explanation:

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3 years ago

Assume that in 2010 the United States will need 2.0×1012 watts of electric power produced by thousands of 1000 MW power plants.

Alex73 [517]

Answer:

1752.14 tonnes per year.

Explanation:

To solve this exercise it is necessary to apply the concepts related to power consumption and power production.

By conservation of energy we know that:

$\dot{P} = \bar{P}$

Where,

$\dot{P} =$ Production of Power

$\bar{P} =$ Consumption of power

Where the production of power would be,

$\dot{P} = m \dot{E}\eta$

Where,

m = Total mass required

$\dot{E} =$ Energy per Kilogram

$\eta =$ Efficiency

The problem gives us the aforementioned values under a production efficiency of 45%, that is,

$\dot{P} = \bar{P}$

$m \dot{E}\eta = \bar{P}$

Replacing the values we have,

$m(8*10^13)(0.45) = 2*10^{12}$

Solving for m,

$m = \frac{ 2*10^{12}}{(8*10^13)(0.45)}$

$m = 0.0556 \frac{kg}{s}$

We have the mass in kilograms and the time in seconds, we need to transform this to tons per year, then,

$m = 0.556\frac{kg}{s}*(\frac{3.1536*10^7s}{1year})(\frac{1ton}{1000kg})$

$m = 1752.14$ tonnes per year.

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3 years ago

A car of mass 1800 kg collides with a truck of mass 5200 kg, and just after the collision the car and truck slide along, stuck t

kupik [55]

Explanation:

Elastic collision is said to occur if the total kinetic energy is not conserved and if there is a rebound after collision

Step one

Analysis of the problem

Immediately after impact the car's velocity was zero making it a perfect elastic collision

Step two

Given

Mass of car M1=1800kg

Mass of truck M2=5200kg

Initial velocity of Car U1=44m/s

Initial velocity of truck U2=21m/s

Final velocity of car V1= 0m/s

Final velocity of truck V2=20m/s

Step three

According to the principle of conservation of momentum

Total momentum before collision

=M1U1+M2U2

Total momentum after impact

=M1V1+M2V2

M1U1+M2U2 =M1V1+M2V2

Substituting our data into the expression we have 1500*44+5800*21=1500*0+5800*20

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Momentum after impact is 11600Ns

This is indicating that after impact there was loss in momentum as a result of the car having a velocity of zero

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4 years ago

A ball is thrown straight up with an initial speed of 50 ms how high does it go?

gavmur [86]

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3 years ago