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zheka24 [161]
3 years ago
10

If you are administering an oral acetaminophen dose of 400. mg from a bottle at a concentration of 32.0 mg/mL , how many millili

ters of the solution do you need to give the patient?
Chemistry
1 answer:
NISA [10]3 years ago
8 0

hey there!:

dose of acetaminophen = 400.

concentration = 32.0 mg/mL

Therefore:

Volume =   dose / concentration

Volume = 400. / 32.0

Volume = 12.5 mL


Hope that helps!

You might be interested in
ch sulfide (ZnS) occurs in the zinc blende crystal structure, (a) If 254 g of ZnS contains 170 g of Zn, what is the mass ratio o
Aleonysh [2.5K]

Answer:

The mass ratio of zinc to sulfide is 85:42.

2.5559 kg of Zn are in 3.82 kg of ZnS.

Explanation:

a) Mass of zinc sulfide = 254 g

Mass of zinc in a zinc sulfide sample = 170 g

Mass of sulfide in zinc sulfide sample = x

254 g = 170 g+ x

x = 84 g

The mass ratio of zinc to sulfide:

\frac{170 g}{84 g}=\frac{85}{42}

b) Mass of zincsulfide sample = 3.83 kg

The mass ratio of zinc to sulfide is 85:42.

Let the mass of zinc and sulfide be 85x and 42x respectively:

85 x+ 42 x=3.82 kg

x =0.03007 kg

Mass of an zinc= 85x=85 × 0.03007 kg= 2.5559 kg

8 0
3 years ago
Perform the following conversions:<br> (a) 68°F (a pleasant spring day) to °C and K.
IgorC [24]

Converting  temperature of 68°F to °C gives 20 °C.

Converting  temperature of 68°F to K gives 293 K.

<h3>What is temperature conversion?</h3>

Temperature conversion is the process of converting  the measurement units of the temperature recorded in a particular unit to another unit.

The various units of Temperature include;

  • degree Celsius
  • degree Fahrenheit
  • degree Kelvin

Temperature is measured with thermometer and it records the hotness or coldness of a body.

<h3>Converting  68°F to °C</h3>

F = 1.8C + 32

(F - 32/1.8) = C

(68 - 32) / 1.8 = C

20 ⁰C = 68 ⁰F

<h3>Converting  20°C to K</h3>

0 °C  = 273 K

20 °C  = 273 + 20 = 293 K

Learn more about temperature conversion here: brainly.com/question/23419049

#SPJ1

3 0
2 years ago
Please help due right now <br> 10 POINTS
Darya [45]

Answer:

F=ma

Explanation:

F=m×a

according to that F÷m=a and also F ÷a=m

3 0
3 years ago
0.500 L of a gas is collected at 2911 MM and 0°C. What will the volume be at STP?
ioda

Answer:

V₂ =  1.92 L

Explanation:

Given data:

Initial volume = 0.500 L

Initial pressure =2911 mmHg (2911/760 = 3.83 atm)

Initial temperature = 0 °C (0 +273 = 273 K)

Final temperature = 273 K

Final volume = ?

Final pressure = 1 atm

Solution:

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

by putting values,

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 3.83 atm × 0.500 L × 273 K / 273 K × 1 atm

V₂ = 522.795 atm .L. K / 273 K.atm

V₂ =  1.92 L

4 0
3 years ago
Suppose 2.8 moles of methane are allowed to react with 5 moles of oxygen.
Ronch [10]

Answer : The limiting reagent is O_2

Solution : Given,

Moles of methane = 2.8 moles

Moles of O_2 = 5 moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

CH_4+2O_2\rightarrow CO_2+2H_2O

From the balanced reaction we conclude that

As, 2 mole of O_2 react with 1 mole of CH_4

So, 5 moles of O_2 react with \frac{5}{2}=2.5 moles of CH_4

From this we conclude that, CH_4 is an excess reagent because the given moles are greater than the required moles and O_2 is a limiting reagent and it limits the formation of product.

Hence, the limiting reagent is O_2

8 0
3 years ago
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