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IRINA_888 [86]
4 years ago
13

Three points, A, B, and C exists in space such that B is "between" A and C. It is known that AB  7 , BC  4 and AC  9 . Are po

ints A, B, and C collinear? Give a written explanation, supported by mathematical evidence, for your answer.
Mathematics
1 answer:
Aleks04 [339]4 years ago
5 0

Answer:

The answer to your question is: the points are not collinear.

Step-by-step explanation:

Data

AB = 7

BC = 4

AC = 9

Are points A,B and C collinear?

If they are collinear, the distance from AB plus the distance BC must be equal to the distance AC.

Process

                 dAB    +     d dBC     =     d AC

                  7         +    4              =     9

                                     11           =    9  

The distances are different so they are no collinear

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Read 2 more answers
Two Aps have the same first and last terms .The first Ap has 21 terms with a common difference of nine how many terms has the ot
Pani-rosa [81]

Answer:

46 terms

Step-by-step explanation:

a₁=b, a₂₁= bₙ, d₁=9, d₂=4

n=?

---------------

a₂₁= a₁+20d₁= a₁+20*9= a₁+180

bₙ= b₁+(n-1)d₂= a₁+4(n-1)

a₁+4(n-1)=a₁+180

4(n-1)=180

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7 0
4 years ago
Hurry!
NARA [144]

Ans(a):

Given function is f(x)=\frac{3x-1}{x+4}

we know that any rational function is not defined when denominator is 0 so that means denominator x+4 can't be 0

so let's solve

x+4≠0 for x

x≠0-4

x≠-4

Hence at x=4, function can't have solution.


Ans(b):

We know that vertical shift occurs when we add something on the right side of function so vertical shift by 4 units means add 4 to f(x)

so we get:

g(x)=f(x)+4

g(x)=\frac{3x-1}{x+4}+4

We may simplify this equation but that is not compulsory.

Comparision:  

Graph of g(x) will be just 4 unit upward than graph of f(x).


Ans(c):

To find value of x when g(x)=8, just plug g(x)=8 in previous equation

8=\frac{3x-1}{x+4}+4


8-4=\frac{3x-1}{x+4}


4=\frac{3x-1}{x+4}


4(x+4)=(3x-1)


4x+16=3x-1


4x-3x=-1-16

x=-17

Hence final answer is x=-17

8 0
4 years ago
Which expression is equivalent to 4(x^3)(2x)^-4
AVprozaik [17]

Answer:

=\frac{4x^{3}}{16 x^{4}}

Step-by-step explanation:

4(x^{3} )(2x)^{-4}

=\frac{4x^{3}}{(2x)^{4}}

=\frac{4x^{3}}{2^{4} x^{4}}

=\frac{4x^{3}}{16 x^{4}}

3 0
3 years ago
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