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mrs_skeptik [129]
3 years ago
13

2,2,3,8,10 mean, median , range

Physics
2 answers:
wariber [46]3 years ago
7 0

Answer:

mean=5

median=3

range=8

Explanation:

mean- add em up and divide by the number of numbers

so 2+2+3+8+10=4+11+10+15+10=25

There are 5 numbers so 25/5=5 is the mean

median- middle (or average of middles if two middles)  after data arranged from least to greatest

It already is and there is one middle so the median is 3

range=greatest minus smallest

So the range is 10-2=8.

saveliy_v [14]3 years ago
5 0

The mean is the average so add up all the numbers and divide by the amount of numbers. This gives you 5 for the mean

The median is the middle number when they are lined up in number order. That number in this list is 3

Range is the largest number subtracted by the smallest number. 10-2=8

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A capacitor with initial charge q0 is discharged through a resistor. a) In terms of the time constant τ, how long is required fo
-BARSIC- [3]

Answer:

It would take \tau(\ln 9 - \ln 8) time for the capacitor to discharge from q_0 to \displaystyle \frac{8}{9} \, q_0.

It would take \tau(\ln 9 - \ln 7) time for the capacitor to discharge from q_0 to \displaystyle \frac{7}{9}\, q_0.

Note that \ln 9 = 2\,\ln 3, and that\ln 8 = 3\, \ln 2.

Explanation:

In an RC circuit, a capacitor is connected directly to a resistor. Let the time constant of this circuit is \tau, and the initial charge of the capacitor be q_0. Then at time t, the charge stored in the capacitor would be:

\displaystyle q(t) = q_0 \, e^{-t / \tau}.

<h3>a)</h3>

\displaystyle q(t) = \left(1 - \frac{1}{9}\right) \, q_0 = \frac{8}{9}\, q_0.

Apply the equation \displaystyle q(t) = q_0 \, e^{-t / \tau}:

\displaystyle \frac{8}{9}\, q_0 = q_0 \, e^{-t/\tau}.

The goal is to solve for t in terms of \tau. Rearrange the equation:

\displaystyle e^{-t/\tau} = \frac{8}{9}.

Take the natural logarithm of both sides:

\displaystyle \ln\, e^{-t/\tau} = \ln \frac{8}{9}.

\displaystyle -\frac{t}{\tau} = \ln 8 - \ln 9.

t = - \tau \, \left(\ln 8 - \ln 9\right) = \tau(\ln 9 - \ln 8).

<h3>b)</h3>

\displaystyle q(t) = \left(1 - \frac{1}{9}\right) \, q_0 = \frac{7}{9}\, q_0.

Apply the equation \displaystyle q(t) = q_0 \, e^{-t / \tau}:

\displaystyle \frac{7}{9}\, q_0 = q_0 \, e^{-t/\tau}.

The goal is to solve for t in terms of \tau. Rearrange the equation:

\displaystyle e^{-t/\tau} = \frac{7}{9}.

Take the natural logarithm of both sides:

\displaystyle \ln\, e^{-t/\tau} = \ln \frac{7}{9}.

\displaystyle -\frac{t}{\tau} = \ln 7 - \ln 9.

t = - \tau \, \left(\ln 7 - \ln 9\right) = \tau(\ln 9 - \ln 7).

7 0
3 years ago
Im confused about something... how many years would it take to reach the sun..
zysi [14]

Answer:

I would take 19.3 year to fly to the sun

6 0
3 years ago
A 10-cm-thick aluminum plate (α = 97.1 × 10−6 m2/s) is being heated in liquid with temperature of 550°C. The aluminum plate has
Zarrin [17]

Answer:

356°C.

Explanation:

(1). The first step to the solution to this particular Question/problem is to determine the Biot number, and after that to check the equivalent value of the Biot number with plate constants.

That is, Biot number = (length × ∞)÷ thermal conductivity. Which gives us the answer as ∞. Therefore, the equivalent value of the ∞ on the plates constant = 1.2732 for A and 1.5708 for λ.

(2). The next thing to do is to determine the fourier number.

fourier number = [α = 97.1 × 10−6 m2/s × 15 s] ÷ (.05m)^2 = 0.5826.

(3). The next thing is to determine the temperature at the center plane after 15 s of heating.

The temperature at the center plane after 15 s of heating = 500°C [ 25°C - 500°C ] [1.2732] × e^(-1.5708)^2 ( 0.5826).

The temperature at the center plane after 15 s of heating = 356°C.

8 0
3 years ago
1. A 1000 kg bag of sand has an<br> acceleration of 0.5m/s/s. What is the<br> force on the bag?
densk [106]

Answer:

We conclude that the force on the bag is 500 N.

Explanation:

Given

  • Mass m = 1000 kg
  • Acceleration a = 0.5 m/s²

To determine

Force F = ?

We know that when a force is applied to a body, it produces acceleration.

<u>Important Tip: </u>

  • We can determine the force on the bag using the formula F = ma

Using the formula

F = ma

where

  • F is the force
  • m is the mass
  • a is the acceleration

now substitute m = 1000, and a = 0.5 m/s² in the formula

F = ma

F = (1000)(0.5)

F=500 N

Therefore, we conclude that the force on the bag is 500 N.

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3 years ago
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