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erastovalidia [21]
3 years ago
15

1. How does adding energy to a solid affect the motion of the particles? 2. How can a gas at room temperature (like oxygen) beco

me solid?​
Chemistry
1 answer:
Oksanka [162]3 years ago
6 0
I am not sure sorry
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How many sig figs 18.01528
Ulleksa [173]

Answer:7

Explanation:

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3 years ago
Which of the following list all the elements that are present in a molecule of potassium carbonate K2C03?
meriva
H
Since K stands for potassium, C stands for Carbon and O stands for Oxygen
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3 years ago
This picture shows students working in a
Lilit [14]

Answer:

yes it is true they apply necessary safety measures

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3 years ago
How many liters of CH, gas are in 5.40 moles of CH, gas at STP?<br> (3 sig figs)
charle [14.2K]

Answer:

Try this link https://chem.libretexts.org/Courses/Mount_Aloysius_College/CHEM_100%3A_General_Chemistry_(O'Connor)/08%3A_Solids_Liquids_and_Gases/8.E%3A_Solids_Liquids_and_Gases_(Exercises)

5 0
3 years ago
54.56 g of water at 80.4 oC is added to a calorimeter that contains 47.24 g of water at 40 oC. If the final temperature of the s
fomenos

Answer:

49.5J/°C

Explanation:

The hot water lost some energy that is gained for cold water and the calorimeter.

The equation is:

Q(Hot water) = Q(Cold water) + Q(Calorimeter)

<em>Where:</em>

Q(Hot water) = S*m*ΔT = 4.184J/g°C*54.56g*(80.4°C-59.4°C) = 4794J

Q(Cold water) = S*m*ΔT = 4.184J/g°C*47.24g*(59.4°C-40°C) = 3834J

That means the heat gained by the calorimeter is

Q(Calorimeter) = 4794J - 3834J = 960J

The calorimeter constant is the heat gained per °C. The change in temperature of the calorimeter is:

59.4°C-40°C = 19.4°C

And calorimeter constant is:

960J/19.4°C =

<h3>49.5J/°C</h3>

<em />

7 0
3 years ago
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