Two ways that weak nuclear forces and electromagnetic forces are simaliar

A dock worker loading crates on a ship finds that a 27 kg crate, initially at rest on a horizontal surface, requires a 80 N hori

Aleksandr-060686 [28]

Answer:0.302

Explanation:

Given

mass of crate m=27 kg

Force required to set crate in motion is 80 N

Once the crate is set in motion 56 N is require to move it with constant velocity

i.e. 80 N is the amount of force needed to just overcome static friction and 56 is the kinetic friction force

thus

$f_s(static\ friction)=\mu \cdot N$

where $\mu$ is the coefficient of static friction and N is Normal reaction

$N=mg$

$f_s=\mu mg$

$\mu mg=80$

$\mu =\frac{80}{27\times 9.8}$

$\mu =0.302$

7 0

4 years ago

When sugar or another substance is dissolved in water, it disappears from view and forms a homogeneous mixture with the water, a

adoni [48]

You can tell if the sugar is still there by boiling off the water and leaving the sugar behind in the container. Sugar is a solid, and therefore cannot evaporate, so when the water reaches boiling point, it will evaporate at a quicker rate than before (water evaporates at any temperature in liquid form; just not enough to be noticeable) and leave the container to become water vapour

6 0

3 years ago

Where would a bowling ball and a napkin fall with the same acceleration?

schepotkina [342]

That would happen at any place where they don't have to
fall through air or anything else.

Examples:

-- on the moon
-- on an asteroid
-- on a comet
-- on Mercury
-- on Earth, in a vacuum chamber with all the air pumped out of it

5 0

3 years ago

Read 2 more answers

A 22 µF capacitor charged to 0.7 kV and a second 115 µF capacitor charged to 5.5 kV are connected to each other, with the positi

vesna_86 [32]

Answer:

0.099C

Explanation:

First, we need to get the common potential voltage using the formula

$V=\frac {C_2V_2-C_1V_1}{C_1+C_2}$

Where V is the common voltage, C and V represent capacitance and charge respectively. Subscripts 1 and 2 to represent the the first and second respectively. Substituting the above with the following given values then

$C_1=22\times 10^{-6} F\\ C_2=115\times 10^{-6} F\\ V_1= 0.7\times 10^{3}\\V_2=5.5\times 10^{3}$