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andrey2020 [161]

2 years ago

12

2(sqrt(9,000,000/2)) 9,000,000/(sqrt(9,000,000/2))

1 answer:

Bingel [31]2 years ago

7 0

<span>2(sqrt(9,000,000/2)) 9,000,000/(sqrt(9,000,000/2)) The answer is 18,000,000 or 18 Million my friend.</span>

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If j is 52° and its a right angle, add 90° and 52°. Then subtract 180° from that answer. Because all triangles add up to 180°.

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3 years ago

I’ll give you all my love and affection if you help me with this ASAP PLEASE ;)

guapka [62]

Answer: (12,0)

Steps:

First, put the equation in slope-intercept form.

y=mx+b

1.5x + 4.5y =18

Subtract 1.5x from both sides.

4.5y =-1.5x +18

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Then replace y with 0 because the point for the x-intercept is exactly on the x-axis so the y=0.

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4 0

3 years ago

Roman solved the equation 5a+2b=10 for a. His steps are shown below. 1. Subtract 2b: 5a+2b-2b=10-2b 2. Multiply by 5: 5a+10-2b W

VladimirAG [237]

Answer:

In step 2, he needed to divide both sides of the equation by 5

Step-by-step explanation:

we have

$5a+2b=10$

Solve for a------> That means isolate the variable "a"

step 1

Subtract 2b to both sides

$5a+2b-2b=10-2b$

$5a=10-2b$

step 2

Divide by 5 both sides

$5a/5=(10-2b)/5$

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3 0

2 years ago

Read 2 more answers

Perform the indicated operation. Be sure the answer is reduced.

avanturin [10]

<h3>Given Equation:-</h3>

$\boxed{ \rm \frac{4x^{2}y^{3}z}{9} \times \frac{45y}{8 {x}^{5} {z}^{5} }}$

<h3>Step by step expansion:</h3>

$\dashrightarrow \sf\dfrac{4x^{2}y^{3}z}{9} \times \dfrac{45y}{8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{ \cancel4x^{2}y^{3}z}{9} \times \dfrac{45y}{ \cancel8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{9} \times \dfrac{45y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{ \cancel9} \times \dfrac{ \cancel{45}y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{0}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5 - 2} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z}{1} \times \dfrac{5y}{2{x}^{3} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z {}^{0} }{1} \times \dfrac{5y}{2{x}^{3} {z}^{3 - 1} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}}{1} \times \dfrac{5y}{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y \times {y}^{3} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y {}^{0} \times {y}^{3 + 1} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5 \times {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \bf \dfrac{5 {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\therefore \underline{ \textbf{ \textsf{option \red c \: is \: correct}}}$

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2 years ago

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lana66690 [7]

Answer:

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Step-by-step explanation:

6 0

3 years ago

Read 2 more answers