Answer:
1 : 3
Step-by-step explanation:
Given the following :
First day :
Patient received = 24
Patient discharged = 6
Second day :
Patient received = 8
Patient discharged = 21
First day :
Patient received = 9
Patient discharged = 6
Number of patient in the hospital at the end of the third day:
Patients received = (24 + 8 + 9) = 41
Patients discharged = (6 + 21 + 6) = 33
Patient received - patient discharged
= (41 - 33) = 8
Number of patients in hospital at the start of the three day period :
Patient received on first day = 24
Patient at the end : patient at the start
8 : 24 = 1 : 3
A function is said to be "undefined" at points outside of its domain.
Answer:
Irrational
Step-by-step explanation:
Repeating decimals are rational. Nonrepeating are irrational.
This is a nonrepeating decimal. First you have one 3, then two 3s, then three 3s. It's not a repeating pattern. So it's an irrational number.
Answer: Please see answer in explanation column
Step-by-step explanation:
Place value tells us how much value or the worth of a number. In a decimal number as such below, The numbers before the decimal point are whole numbers, while after the decimal number are regarded as fractions .
In the number 7.759,
The place value of One of the 7 represents 7 unit = 7.0
and the other 7 represents 7 tenths = 7/ 10 of unit= 0.7
We can see from above the the 7 unit, a whole number is greater than 7 tenths which is a fraction.
Answer and Step-by-step explanation:
All you have to do is find the area of one of the half triangles, multiply that by 2, then multiply it by 4. Then find the area of the square.
Half of 8 is 4, which is the length of the small line of the triangle.
The area of a triangle equation is A = 
.
The area of a square equation is A = LW
<u>Triangle:</u>
The small triangle area is 20, so one triangle face of the square pyramid is 40.
40 times 4 is 160.
<u>Square:</u>
8 × 8 = 64
The area of the square is 64.
Now add together the areas.
<u>Surface area:</u>
160 + 64 = 224
<u>The surface area of the square pyramid is 224 </u>
<u>.</u>
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