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Hoochie [10]
3 years ago
14

How many milliliters of 0.200 M FeCl3 are needed to react with an excess of Na2S to produce 0.345 g of Fe2S3 if the percent yiel

d for the reaction is 65.0%? 3 Na2S(aq) + 2 FeCl3(aq) →→ Fe2S3(s) + 6 NaCl(aq)
Chemistry
1 answer:
GuDViN [60]3 years ago
8 0

Answer:

25.53mL of 0.200 M FeCl₃ are needed to produce 0.345g of Fe₂S₃

Explanation:

Based on the reaction of the problem, 1 mole of Fe₂S₃ is produced from 2 moles of FeCl₃.

0.345g of Fe₂S₃ are (Molar mass: 207.9g/mol):

0.345g of Fe₂S₃ ₓ (1 mol / 207.9g) = <em>1.6595x10⁻³ moles Fe₂S₃</em>

Moles of Fe needed to produce these moles of Fe₂S₃ are:

1.6595x10⁻³ moles Fe₂S₃ ₓ ( 2 moles FeCl₃ / 1 mole Fe₂S₃) =

<em>3.3189x10⁻³ moles of FeCl₃</em>

As the percent yield of the reaction is 65.0%, the moles of FeCl₃ you need to add are:

3.3189x10⁻³ moles of FeCl₃ ₓ (100.0% / 65.0%) = <em>5.106x10⁻³ moles of FeCl₃</em>

A solution 0.200M contains 0.200 moles per L. Volume to obtain 5.106x10⁻³ moles is:

<em>5.106x10⁻³ moles of FeCl₃ ₓ ( 1L / 0.200mol) = 0.02553L = </em>

<h3>25.53mL of 0.200 M FeCl₃ are needed to produce 0.345g of Fe₂S₃</h3>

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kvasek [131]

Answer:

so the number of molecules in 8 moles of water is 4.8176×10^24

Explanation:

number of moles=8moles

avogadro's number=6.022×10²³

number of molecules=?

as we know that

number of moles=\frac{number of molecules}{avogadro's number}

substituting the equation

number of moles × avogdro's number=number of molecules

number of molecules=8moles×6.022×10²³

number of molecules=4.8176×10^24

i hope this will help you :)

4 0
3 years ago
At room temperature (208C) and pressure, the density of air is 1.189 g/L. An object will float in air if its density is less tha
Ugo [173]

Total density of filled ball with nitrogen gas: \frac{0.12G+0.6524g}{0.560L} = 1.3792g/L

The relationship between mass and volume can be easily determined using density; for example, the mass of a body is equal to its volume multiplied by the density (M = Vd), whereas the volume is equal to the mass divided by the density (V = M/d). The ball filled with nitrogen will not float in the air because total density of filled ball is greater than the density of an air. Density of the evacuated ball D = 0.214 g/L

Density of nitrogen gas = d_4=1.165g/L

Mass of the nitrogen gas : 1.165g/L \times 0.560L = 0.6524g

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4 0
1 year ago
Which radiation can only be stopped by thick layers of dense metal? (2 points)
AfilCa [17]
Gamma rays have the highest penetrating power so it can only be stopped by thick layers of dense metal. :)
5 0
3 years ago
Read 2 more answers
How many moles of HCl are present in 4.7 L of a 4.23 M HCl solution?
REY [17]

Hey There!

Volume = 4.7 L

Molarity = 4.23 M

Therefore:

n = M *V

n = 4.23 * 4.7

n = 19.881 moles of HCl

hope this helps!

6 0
3 years ago
You have 100 g of Pb(NO3)2. How many moles is this?​
topjm [15]

Answer:

0.302 moles

Explanation:

Data given

Mass of Pb(NO₃)₂ = 100 g

Moles of Pb(NO₃)₂ = ?

Solution:

To find mole we have to know about molar mass of Pb(NO₃)₂  

So,

Molar mass of Pb(NO₃)₂  = 207 + 2[14 + 3(16)]

                                           = 207 + 2[14 + 48]

                                           = 207 + 124

Molar mass of Pb(NO₃)₂  = 331 g/mol

Formula used :

                no. of moles = mass in grams / molar mass

Put values in above formula

                   no. of moles = 100 g / 331 g/mol

                   no. of moles = 0.302 moles

no. of moles of  Pb(NO₃)₂ = 0.302 moles

7 0
3 years ago
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