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lina2011 [118]
4 years ago
10

Simplify (4^3)^5 - - - - -

Mathematics
2 answers:
MissTica4 years ago
6 0

Answer:

\large\boxed{(4^3)^5=4^{15}}

Step-by-step explanation:

\text{Use}\ (a^n)^m=a^{nm}\\\\(4^3)^5=4^{(3)(5)}=4^{15}

Slav-nsk [51]4 years ago
5 0

Step-by-step explanation: Here we have the number  (4^3)^5.

We can use the relationship: (x^{a} )^{b} = x^{a*b}

so our number can be written as: (4^{3}) ^{5} = 4^{3*5} = 4^{15}.

But you can simplify it further!

we know that 4 = 2^{2}, then 4^{15} = (2^{2}) ^{15} = 2^{2*15} = 2^{30}

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The paths walked by two different people are represented by the vectors graphed below.
Readme [11.4K]

Answer:

8,6

Step-by-step explanation:

if its the sum, you just add them together.

5 0
3 years ago
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Andrew is working for his mother's company this summer. He gets paid $0.31 for every 4 words he types. If he wants to earn $175
mestny [16]

Answer:

2,258

Step-by-step explanation:

4 words = $0.31

\frac{4}{0.31} = \frac{x}{175}

cross multiple and solve for x

0.31x = (175)(4)

x = about 2,258

4 0
3 years ago
Suppose 40% of DC area adults have traveled outside of the United States. Nardole wants to know if his customers are atypical in
Sonbull [250]

Answer:

We conclude that % of DC area adults who have traveled outside of the United States is different from 40%.

Step-by-step explanation:

We are given that 40% of DC area adults have traveled outside of the United States. Nardole wants to know if his customers are typical in this respect. He surveys 40 customers and finds 60% have traveled outside of the U.S.

We have to test is this result a statistically significant difference.

<em>Let p = % of DC area adults who have traveled outside of the United States</em>

SO, Null Hypothesis, H_0 : p = 40%  {means that 40% of DC area adults have traveled outside of the United States}

Alternate Hypothesis, H_a : p \neq 40%  {means that % of DC area adults who have traveled outside of the United States is different from 40%}

The test statistics that will be used here is <u>One-sample z proportion statistics</u>;

                  T.S. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1- \hat p)}{n} } }  ~ N(0,1)

where, \hat p = % of customers who have traveled outside of the United States

                  in a survey of 40 customers = 60%

          n  = sample of customers = 40

So, <u>test statistics</u> = \frac{0.60-0.40}{\sqrt{\frac{0.60(1-0.60)}{40} } }

                             = 2.582

<em>Since in the question we are not given with the significance level so we assume it to be 5%. So, at 0.05 level of significance, the z table gives critical value of 1.96 for two-tailed test. Since our test statistics is more than the critical value of z so we have sufficient evidence to reject null hypothesis as it will fall in the rejection region.</em>

Therefore, we conclude that % of DC area adults who have traveled outside of the United States is different from 40%.

7 0
3 years ago
Write a mathematical expression for the word phrase -5/6 and 6/5
OLga [1]

Answer:

negative five sixths and six over five so 1 1/5

Step-by-step explanation:


3 0
4 years ago
Help me I'm lost and need answers
Murljashka [212]
You can look it up on math
way 
4 0
3 years ago
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