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Pani-rosa [81]
3 years ago
13

What does training for hypertrophy do to your body

Physics
2 answers:
sergeinik [125]3 years ago
6 0
Answer: A increases muscle size

Explanation:
VikaD [51]3 years ago
5 0

Answer:

The answer is A.

Explanation:

Hypertrophy is an increase and growth of muscle cells. Hypertrophy refers to an increase in muscular size achieved through exercise. When you work out, if you want to tone or improve muscle definition, lifting weights is the most common way to increase hypertrophy.

Hope that helped.

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After a laser bean passes through two thin parallel slits, thefirst completely dark fringes occur at ± 15.00with the original di
PSYCHO15rus [73]

Answer:

143 °

Explanation:

a ) If d be the distance between slits , λ be wavelength of light used and at angle θ nth dark fringe is formed then

d sinθ = ( 2n+1) λ/2

for first dark fringe

d sinθ = λ/2

d /λ = 1/ 2 sinθ

1 / 2 sin15

= 1.93

b )

For intensity of fringe at angle θ,  the relation is

I = I₀ cos²θ

I / I₀  = cos²θ/2

Given I / I₀ =0. 1

0.1 = cos²θ/2

θ/2 = 71.5

θ = 143 °

4 0
3 years ago
If you were creating a presentation that would cover the different types of muscles in the body, which groups of muscle would yo
diamong [38]
It would be best to cover the cardiac, smooth, and skeletal muscles! =)
6 0
3 years ago
Read 2 more answers
What is the velocity of a car that travels 1,069 meters in 54 seconds?
irga5000 [103]

Answer:

20.41m/s. hdjdgshd

Explanation:

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8 0
3 years ago
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a place that is typically cold because of an increase in altitude would most likely have what type of climate? dry climate mild
Marta_Voda [28]
A place that is cold because of an increase in altitude has a mountain area climate or simply, mountain climate. An area that is high in altitude typically has a colder temperature because of the increased amount of rainfall they have. Also, air tends to cool as it rises in temperature. 
3 0
3 years ago
Oil having a density of 926 kg/m3 floats on water. A rectangular block of wood 3.69 cm high and with a density of 974 kg/m3 floa
zloy xaker [14]

Answer:

the position of the wood below the interface of the two liquids is 2.39 cm.

Explanation:

Given;

density of oil, \rho _o = 926 kg/m³

density of the wood, \rho _{wood} = 974 kg/m³

density of water, \rho _w = 1000 kg/m³

height of the wood, h = 3.69 cm

Based on the density of the wood, it will position across the two liquids.

let the position of the wood below the interface of the two liquids = x

Let the wood be in equilibrium position;

F_{wood} - F_{oil} - F_{water} = 0\\\\\rho _{wood} .gh - \rho _o .g(h-x) - \rho_w .gx = 0\\\\\rho _{wood} .h - \rho _o (h-x) - \rho_w .x = 0\\\\\rho _{wood} .h -\rho _o h + \rho _o x - \rho_w .x =0\\\\h (\rho _{wood}  -\rho _o ) = x( \rho_w - \rho _o)\\\\x =h[\frac{ \rho _{wood}  -\rho _o }{\rho_w - \rho _o} ]\\\\x = 3.69\ cm \times [\frac{974 - 926}{1000-926} ]\\\\x = 2.39 \ cm

Therefore, the position of the wood below the interface of the two liquids is 2.39 cm.

6 0
3 years ago
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