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3 years ago

When doing a squat, how do you do it without getting hurt?

Physics

2 answers:

Aleksandr [31]3 years ago

7 0

I do weight lifting so you need feet flat on floor but out back straight and also a spotter

padilas [110]3 years ago

6 0

Make sure your feet and shoulder width apart, and parallel to each other also when you do the squat make sure your knees dont pass your toes and keep your back straight!:) have fun

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Pls help me solve these questions.

aliina [53]

The value of constant in terms of Force, k, A, V and ρ is x = ln (F /kAρV ).

<h3>What is opposing force?</h3>

The force which tends to oppose motion of fluid in forward direction like shear stress in liquids and friction force in solids

A body moving through the air at speed V, experiences the retarding force.

Force = kAρVˣ

where A is the surface area, ρ is the density of air and k is the numerical constant.

Taking natural logarithm both sides,

ln F = ln (kAρVˣ)

ln F = x ln (kAρV)

x = ln F / ln (kAρV)

x= ln (F /kAρV )

x= ln F - ln (kAρV)

Thus, the value of constant is deduced in terms of Force , k, A, V and ρ.

Learn about opposing force.

brainly.com/question/13191643

#SPJ1

5 0

2 years ago

In a science fiction novel two enemies, Bonzo and Ender, are fighting in outer spce. From stationary positions, they push agains

Bingel [31]

Answer:

2.461

Explanation:

Let mass of Bonzo = m1

Mass of Ender =m2

When they push eachother from stationary position

Initial velocity of Bonzo = Vib=0 m/s

Final velocity of Bonzo = Vfb= 1.3 m/s

Initial velocity of Ender = Vie= 0 m/s

Final velocity of Ender = Vfe= -3.1 m/s

We know initial momentum = final momentum

==> m1Vib+m2Vie = m1Vfb+m2Vfe

==> 0+0= m1×1.3 +m2×(-3.1)

==> 1.3m1-3.1m2=0

==> 1.3 m1 = 3.2 m2

==> m1/m2 = 3.2/1.3

==> m1/m2 = 2.461

6 0

3 years ago

A horizontal 791-N merry-go-round is a solid disk of radius 1.56 m and is started from rest by a constant horizontal force of 49

ICE Princess25 [194]

Answer:

$K.E=273.5J$

Explanation:

Given data

$F_{g}=791N\\F_{h}=49N\\r=1.56m\\t=3.03s$

To find

Kinetic Energy

Solution

The moment of inertia is given as:

$I=(\frac{1}{2} )MR^2\\I=\frac{1}{2}(F_{g}/g)R^2\\ I=\frac{1}{2}(\frac{791N}{9.8m/s^2} )(1.56m)^2\\ I=98.21kg.m^2$

The angular acceleration is given as:

$\alpha =\frac{T}{I}\\\alpha =\frac{F_{y}R}{I}\\ \alpha =\frac{(49N)(1.56m)}{98.2kg.m^2}\\\alpha =0.778rad/s^2$

Now the angular velocity is given by:

$w=\alpha t\\w=(0.778rad/s^2)(3.03s)\\w=2.36rad/s$

So the kinetic energy given as:

$K.E=(\frac{1}{2} )Iw^2\\K.E=\frac{1}{2}(98.21kg.m^2)(2.36rad/s)^2\\ K.E=273.5J$

8 0

3 years ago

Q. No. 9 A body falls freely from the top of a tower and during the last second of its fall, it falls through 25m. Find the heig

HACTEHA [7]

Answer:

45.6m

Explanation:

The equation for the position y of an object in free fall is:

$y=-\frac{1}{2} gt^2+v_0t+y_0$

With the given values in the question the equation has one unknown v₀:

$v_0=\frac{y-y_0}{t}+\frac{1}{2}gt$

Solving for t=1:

1) $v_0=y-y_0+\frac{g}{2}$

To find the hight of the tower you can use the concept of energy conservation:

The energy of the body 1 sec before it hits the ground:

2) $E=\frac{1}{2}m{v_0}^2+mgy_0$

If h is the height of the tower, the energy on top of the tower:

3) $E=mgh$

Combining equation 2 and 3 and solving for h:

4) $h=\frac{{v_0}^2}{2g}+y_0$

Combining equation 1 and 4:

$h=\frac{{(y-y_0+\frac{g}{2}})^2}{2g}+y_0$

4 0

3 years ago

Suppose you wanted to start a fire using sunlight and a mirror. Which of the following statements is most accurate? A) It would

Maru [420]

<h2>Answer: B) It would be best to use a concave mirror, with the object to be ignited positioned halfway between the mirror and its center of curvature. </h2>

Explanation:

To start a fire it is more optimal to use a concave mirror than a plane mirror. This is because the concave mirror allows concentrating sunlight at a point (the focal point) on an object that acts as fuel and ignite the fire there.

For this it is necessary the object to be positioned between the center of curvature of the mirror and the mirror (its focus). Thus the rays of the Sun, when converging on the focus, will heat the object and make it burn.

Hence, the correct option is B.

6 0

4 years ago