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ella [17]
2 years ago
9

A weather balloon is filled to a volume of 2 liters with helium gas at a pressure of 101 kPa, at a temperature of 22oC. The ball

oon is released and floats to a height where the pressure is 90 kPa and the air temperature is now 16oC. What is the new volume of the weather balloon?
Physics
2 answers:
kvv77 [185]2 years ago
7 0

Answer: The new volume of  weather balloon will be 2.2 Liters

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas =  101 kPa

P_2 = final pressure of gas = 90 kpa

V_1 = initial volume of gas = 2 L

V_2 = final volume of gas = ? L

T_1 = initial temperature of gas = 22^oC=273+22=295K

T_2 = final temperature of gas = 16^oC=273+16=289K

Now put all the given values in the above equation, we get the final pressure of gas.

\frac{101\times 2L}{295K}=\frac{90\times V_2}{289K}

V_2=2.2L

Therefore, the volume will be 2.2 Liters.

OLEGan [10]2 years ago
4 0
The answer is B (: Hope it helps

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