The acceleration of the boat is
(eastward)
Explanation:
We can solve this problem by using Newton's second law, which states that:
F = ma (1)
where
F is the net force on a body
m is its mass
a is its acceleration
First of all, we have to find the net force acting on the boat. We have:
- The force of the motor, 100 N eastward
- The force of the air resistance, 60 N westward
So the net force is:
F = 100 N - 60 N = 40 N (eastward)
Now we can apply eq.(1), using:
F = 40 N
m = 20 kg (mass of the boat)
and solving for a, we find the acceleration:

And the direction is the same as the net force (eastward).
Learn more about acceleration and Newton laws of motion:
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#LearnwithBrainly
The sun heats the Earth through the process of radiation.
Hope this helps,
Davinia.
Answer:
(a) The length of the pendulum on Earth is 36.8cm
(b) The length of the pendulum on Mars is 13.5cm
(c) Mass suspended from the spring on Earth is 0.37kg
(d) Mass suspended from the spring on Mars is 0.36kg
Explanation:
Period = 1.2s, free fall acceleration on Earth = 9.8m/s^2, free fall acceleration on Mars = 3.7m/s^2
( a) Length of pendulum on Earth = [( period ÷ 2π)^2] × acceleration = (1.2 ÷ 2×3.142)^2 × 9.8 = 0.0365×9.8 = 0.358m = 35.8cm
(b) Length of the pendulum on Mars = (1.2÷2×3.142)^2 × 3.7 = 0.0365×3.7 = 0.135cm = 13.5m
(c) Mass suspended from the spring on Earth = (force constant×length in meter) ÷ acceleration = (10×0.358) ÷ 9.8 = 0.37kg
(d) Mass suspended from the spring on Mars = (10×0.135)÷3.7 = 0.36kg
A raging activity can be found in t<span>he Sun's interior, with pressure waves being produced and travelling back and forth, from the core to the surface and back to the core. By looking closely at the 'surface' we can see these "ripples". It gives us an idea of how dense the material was that the waves passed through. In a way, this can help to predict solar storms in the future.</span>
Answer:
The value is 
Explanation:
From the question we are told that
The mass of matter converted to energy on first test is 
The mass of matter converted to energy on second test 
Generally the amount of energy that was released by the explosion is mathematically represented as

=> ![E = 1.5 *10^{-3} * [ 3.0 *10^{8}]^2](https://tex.z-dn.net/?f=E%20%3D%20%201.5%20%2A10%5E%7B-3%7D%20%20%2A%20%5B%203.0%20%2A10%5E%7B8%7D%5D%5E2)
=> 