Question

A car is traveling north at 17.7m/s After 12 s its velocity is 14.1m/s in the same direction. Find the magnitude and direction of the car's average acceleration.A2.7 m/s2, north b0.30 m/s2, south c2.7 m/s2, south d0.30 m/s2, north

Answer 1

Answer:

Option B

0.3 m/s2 South

Explanation:

Acceleration, $a=\frac {v-u}{t}$ where v and u are final and initial velocities respectively, t is the time taken

Substituting 14.1 m/s for v, 17.7 m/s for u and 12 s for t then

$a=\frac {14.1 m/s- 17.7 m/s}{12}=-0.3 m/s^{2}$

Since this is negative acceleration, it's direction is opposite hence 0.3 m/s2 South