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2 years ago

Which angle (A, B, or C) is the diffraction angle?

Physics

2 answers:

lisov135 [29]2 years ago

8 0

C is the diffraction angle.... step by step explanation= I think it’s that I might be wrong lol

Ludmilka [50]2 years ago

6 0

Answer:

Explanation:

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Radiant energy travels in straight lines until it strikes an object where it can be ______,_____or transmitted

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Radiant energy travels in straight lines until it strikes an object where it can be absorbed, reflected or transmitted

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2 years ago

Can anyone explain if knows

Aleks [24]

Answer:

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Explanation:

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2 years ago

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In a 2-dimensional coordinate system, the x- and y-axes are typically _____.

dem82 [27]

In a 2-dimensional coordinate system, the x- and y-axes
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3 years ago

The kinetic energy of a proton and that of an a-particle are 4 eV and 1 eV,

madam [21]

Answer:

(b) 1:1

Explanation:

1. Formulae:

E = hf

E = h.v/λ

λ = h/(mv)

E = (1/2)mv²

Where:

E = kinetic energy of the particle
λ = de-Broglie wavelength
m = mass of the particle
v = speed of the particle
h = Planck constant

2. Reasoning

An alha particle contains 2 neutrons and 2 protons, thus its mass number is 4.

A proton has mass number 1.

Thus, the relative masses of an alpha particle and a proton are:

$\dfrac{m_\alpha}{m_p}=4$

For the kinetic energies you find:

$\dfrac{E_\alpha}{E_p}=\dfrac{m_\alpha \times v_\alpha^2}{m_p\times v_p^2}$

$\dfrac{1eV}{4eV}=\dfrac{4\times v_\alpha^2}{1\times v_p^2}\\\\\\\dfrac{v_p^2}{v_\alpha^2}=16\\\\\\\dfrac{v_p}{v_\alpha}=4$

Thus:

$\dfrac{m_\alpha}{m_p}=4=\dfrac{v_p}{v__\alpha}$

$m_\alpha v_\alpha=m_pv_p$

From de-Broglie equation, λ = h/(mv)

$\dfrac{\lambda_p}{\lambda_\alpha}=\dfrac{m_\lambda v_\lambda}{m_pv_p}=\dfrac{1}{1}=1:1$

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3 years ago

The relationship between distance from the sun and orbital period is that as the distance from the sun increases, the orbital pe

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Second law is it:))))))))

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2 years ago