Answer: The answer is C.) 25 m/s^2.
Explanation: If you input 5 as s, you would have to use the exponent 2. This means that you have to multiply 5 by 5. 5 x 5= 25.
Edit: Also, because the surface is frictionless, it will make the object go faster too. Nothing can really slow it down unless something blocks it.
Answer:
= 0.417 m/s
Explanation:
Momentum before throwing the rock: m*V = 95.0 kg * 0.460 m/s
= 44.27 N*s
A) man throws the rock forward
mass of rock m1 = 0.310 kg
V1 = 15.5 m/s, in the same direction of the sled with the man
sled and man:
m2 = 95 kg - 0.310 kg = 94.69 kg
v2 = ?
Conservation of momentum:
momentum before throw = momentum after throw
44.27N*s = 0.310kg * 15.5m/s + 94.69kg*v2
⇒ v2 = [44.27 N*s - 0.310 * 15.5N*s ] / 94.69 kg
= 0.417 m/s
Answer:
P=6.25N and Q=16.25N
Explanation:
In order to solve this problem we must first draw a free body diagram for both situation, (see attached picture).
Now, we need to analyze the two free body diagrams. So let's analyze the first diagram. Since the body is accelerated, then the sum of forces is equal to mass times acceleration, so we get:

We can assume there will be only the two mentioned forces P and Q, so
the sum of forces will be:
P+Q=ma

P+Q=22.5N
We can do the same analysis for the second free body diagram:


Q-P=10.5N
so now we have a system of equations we can solve by elimination:
Q+P=22.5N
Q-P=10.5N
Now, we can add the two equations together so the P force is eliminated, so we get:
2Q=32.5N
now we can solve for Q:

so
Q=16.25N
Now we can use any of the equations to find P.
Q+P=22.5N
P=22.5N-Q
when substituting for Q we get:
P=22.5N-16.25N
so
P=6.25N
I'm not sure what you were trying to put here
Could be easy for some people and hard for some people.