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Allisa [31]
3 years ago
8

Which of the following statements describe the steps you need to take to delete a file?

Physics
2 answers:
Doss [256]3 years ago
6 0
In order to delete a file, it is required to first select the file which you want to delete and then select 'delete' from the file menu. It will then ask you to confirm the deletion which will be required in order to complete the file deletion process.

It isn't required to click on the X at the top right of the screen or to open the file you want to delete as these steps aren't relevant to the deletion process.

Hence, the statements which describe the steps you need to take in order to delete a file are as follows:

- Confirm the deletion.
- Select Delete from the File menu.
- Select the file you want to delete.
olga55 [171]3 years ago
4 0
<h3>Explanation:</h3>

The process is as follows:

Select the file you want to delete.

Select delete from file menu. (You can right click on the file or press delete button on keyboard). A pop would appear which would prompt you to confirm the deletion of the file.

Confirm the deletion.

The x button at the top right would close the file and not delete it. Thus, it is incorrect option.

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A force acts on a 5kg object at rest. How fast will the object accelerate on a frictionless surface?
MakcuM [25]

Answer: The answer is C.) 25 m/s^2.

Explanation: If you input 5 as s, you would have to use the exponent 2.  This means that you have to multiply 5 by 5.  5 x 5= 25.  

Edit: Also, because the surface is frictionless, it will make the object go faster too.  Nothing can really slow it down unless something blocks it.

8 0
3 years ago
A man holding a rock sits on a sled that is sliding across a frozen lake (negligible friction) with a speed of 0.460 m/s. The to
xz_007 [3.2K]

Answer:

= 0.417 m/s

Explanation:

Momentum before throwing the rock: m*V = 95.0 kg * 0.460 m/s

= 44.27 N*s  

A) man throws the rock forward

mass of rock m1 = 0.310 kg

V1 = 15.5 m/s, in the same direction of the sled with the man

sled and man:

m2 = 95 kg - 0.310 kg = 94.69 kg

v2 = ?

Conservation of momentum:

momentum before throw = momentum after throw

44.27N*s = 0.310kg * 15.5m/s + 94.69kg*v2

⇒ v2 = [44.27 N*s - 0.310 * 15.5N*s ] / 94.69 kg

= 0.417 m/s

6 0
4 years ago
Read 2 more answers
Two forces P and Q act on an object of mass 15.0 kg with Q being the larger of the two forces. When both forces are directed to
Rom4ik [11]

Answer:

P=6.25N  and Q=16.25N

Explanation:

In order to solve this problem we must first draw a free body diagram for both situation, (see attached picture).

Now, we need to analyze the two free body diagrams. So let's analyze the first diagram. Since the body is accelerated, then the sum of forces is equal to mass times acceleration, so we get:

\Sigma F=ma

We can assume there will be only the two mentioned forces P and Q, so

the sum of forces will be:

P+Q=ma

P+Q=(15kg)(1.50m/s^{2})

P+Q=22.5N

We can do the same analysis for the second free body diagram:

\Sigma F=ma

Q-P=(15kg)(0.7m/s^{2})

Q-P=10.5N

so now we have a system of equations we can solve by elimination:

Q+P=22.5N

Q-P=10.5N

Now, we can add the two equations together so the P force is eliminated, so we get:

2Q=32.5N

now we can solve for Q:

Q=\frac{32.5N}{2}

so

Q=16.25N

Now we can use any of the equations to find P.

Q+P=22.5N

P=22.5N-Q

when substituting for Q we get:

P=22.5N-16.25N

so

P=6.25N

5 0
4 years ago
Other quanto
Alex73 [517]

I'm not sure what you were trying to put here

5 0
3 years ago
Why is the physics of hssc2 so difficult?
Ivan
Could be easy for some people and hard for some people.
8 0
3 years ago
Read 2 more answers
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