Answer:
An asteroid that has an orbital period of 3 years will have an orbital with a semi-major axis of about 2 years.
Explanation:
Given;
orbital period of 3 years, P = 3 years
To calculate the years of an orbital with a semi-major axis, we apply Kepler's third law.
Kepler's third law;
P² = a³
where;
P is the orbital period
a is the orbital semi-major axis
(3)² = a³
9 = a³
a = ![a = \sqrt[3]{9} \\\\a = 2.08 \ years](https://tex.z-dn.net/?f=a%20%3D%20%5Csqrt%5B3%5D%7B9%7D%20%5C%5C%5C%5Ca%20%3D%202.08%20%5C%20years)
Therefore, An asteroid that has an orbital period of 3 years will have an orbital with a semi-major axis of about 2 years.
When you have several resistors in parallel, their equivalent resistance is the reciprocal of the sum of their individual reciprocals.
When there are only two of them, it gets a lot easier. In that case, their equivalent resistance is equal to
(their product) divided by (their sum).
Equivalent = (7 x 93) / (7 + 93)
Equivalent = (651) / (100)
<em>Equivalent = 6.51 ohms </em>.
Depending on what you are working with, it would be a solid
Answer:
25.2 km east
Explanation:
The relationship between velocity and displacement is given by:

where
v is the velocity
d is the displacement
t is the time
In this problem, we have:
east is Rebecca's velocity
is the time taken
Re-arranging the equation, we can find Rebecca's displacement:

and the direction is same as velocity (east)