Answer:
I think 4 I can't remember
CONVERTS GLUCOSE INTO ENERGY AND WATER
Answer:
D. [CO₂]
Explanation:
Let's consider the following equation at equilibrium.
CaCO₃(s) ⇄ CaO(s) + CO₂(g)
The equilibrium constant, Kc, is the ratio of the equilibrium concentrations of products over the equilibrium concentrations of reactants each raised to the power of their stoichiometric coefficients. It only includes gases and aqueous species.
Kc = [CO₂]
Answer:
- Total Pressure = 1.019 atm
Explanation:
To solve this problem we use PV=nRT for both gases in their containers, in order to <u>calculate the moles of each one</u>:
645 Torr ⇒ 645 /760 = 0.85 atm
25°C ⇒ 25 + 273.16 = 298.16 K
0.85 atm * 1.40 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ *298.16 K
n = 0.0487 mol O₂
1.13 atm * 0.751 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ *298.16 K
n = 0.0347 mol N₂
Now we can <u>calculate the partial pressure for each gas in the new container</u>, because the number of moles did not change:
P(O₂) * 2.00 L = 0.0487 mol O₂ * 0.082 atm·L·mol⁻¹·K⁻¹ *298.16 K
P(O₂) = 0.595 atm
P(N₂) * 2.00 L = 0.0347 mol N₂ * 0.082 atm·L·mol⁻¹·K⁻¹ *298.16 K
P(N₂) = 0.424 atm
Finally we add the partial pressures of all gases to <u>calculate the total pressure</u>:
- Pt = 0.595 atm+ 0.424 atm = 1.019 atm
Answer:
CH₄ and N₂O are not likely to be biologically important greenhouse gases for tree growth
Explanation:
From the discussion of the experiment testing the given hypothesis in the question, all the gases tested, CO2, N2O and CH4 are all green house gases. The aim of the experiment was to ascertain the impact of the selected greenhouse gases on plant biomass. It was observed that CO2 does lead to increase in plant biomass while N2O and CH4 did not.
A proper deduction from the experiment will be 'CH₄ and N₂O are not likely to be biologically important greenhouse gases for tree growth'.
