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3 years ago

What is the mass of H2O produced when 10.0 grams of H2 reacts completely with 80.0 grams of O2?

1 answer:

8 0

H₂:

M=2g/mol
m=10g

n = m/M = 10g/2g/mol = 5mol

O₂:

M = 32g/mol
m = 80g

n = m/M = 80g/32g/mol = 2,5mol

2H₂ + O₂ ⇒ 2H₂O
2mol : 1mol : 2mol
5mol : 2,5mol : 5mol
10g : 80g : 10g+80g=90g

B

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Answer:

Explanation:

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3 years ago

If 0.35 moles of kcl was dissolved in enough water to make 0.2 L of solution, what is molarity?

Mars2501 [29]

Answer:

1.75M

Explanation:

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3 years ago

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Kipish [7]

The answer will be b

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What is the energy released in this β − β − nuclear reaction 40 19 K → 40 20 C a + 0 − 1 e 19 40 K → 20 40 C a + − 1 0 e ? (The

Effectus [21]

<u>Answer:</u> The energy released in the given nuclear reaction is 1.3106 MeV.

<u>Explanation:</u>

For the given nuclear reaction:

$_{19}^{40}\textrm{K}\rightarrow _{20}^{40}\textrm{Ca}+_{-1}^{0}\textrm{e}$

We are given:

Mass of $_{19}^{40}\textrm{K}$ = 39.963998 u

Mass of $_{20}^{40}\textrm{Ca}$ = 39.962591 u

To calculate the mass defect, we use the equation:

$\Delta m=\text{Mass of reactants}-\text{Mass of products}$

Putting values in above equation, we get:

$\Delta m=(39.963998-39.962591)=0.001407u$

To calculate the energy released, we use the equation:

$E=\Delta mc^2\\E=(0.001407u)\times c^2$

$E=(0.001407u)\times (931.5MeV)$ (Conversion factor: $1u=931.5MeV/c^2$ )

$E=1.3106MeV$

Hence, the energy released in the given nuclear reaction is 1.3106 MeV.

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3 years ago

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Answer:

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