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ozzi
3 years ago
9

An object moving with uniform acceleration has a velocity of 14.0 cm/s in the positive x-direction when its x-coordinate is 2.94

cm. If its x-coordinate 1.85 s later is −5.00 cm, what is its acceleration?
Physics
1 answer:
kotykmax [81]3 years ago
8 0

Answer:

-19.9m/s²

Explanation:

Given that

vi = 14cm/s

xi = 2.94 cm

xf=-5.00 cm

t= 1.85s

So

Using xf-xi= vi t + 1/2at²

Which is = -5-2.94= 14*1.85+1/2a1.85²

= -7.94= 25.9+1.7a

-33.9= 1.7a

a= - 19.9m/s²

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3 years ago
A train whistle is heard at 300 Hz as the train approaches town. The train cuts its speed in half as it nears the station, and t
givi [52]

To solve this problem we will apply the concepts related to the Doppler effect. The Doppler effect is the change in the perceived frequency of any wave movement when the emitter, or focus of waves, and the receiver, or observer, move relative to each other. Mathematically it can be described as,

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300 = f_0 (\frac{343}{343-v})

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Now the second expression will be,

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Dividing the two expression we have,

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