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ozzi
3 years ago
9

An object moving with uniform acceleration has a velocity of 14.0 cm/s in the positive x-direction when its x-coordinate is 2.94

cm. If its x-coordinate 1.85 s later is −5.00 cm, what is its acceleration?
Physics
1 answer:
kotykmax [81]3 years ago
8 0

Answer:

-19.9m/s²

Explanation:

Given that

vi = 14cm/s

xi = 2.94 cm

xf=-5.00 cm

t= 1.85s

So

Using xf-xi= vi t + 1/2at²

Which is = -5-2.94= 14*1.85+1/2a1.85²

= -7.94= 25.9+1.7a

-33.9= 1.7a

a= - 19.9m/s²

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if you crash your car how could you decrease the damage to you or the car using the concept of impulse
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Explanation:

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3 years ago
During an investigation, a scientist heated 123.6 g of copper carbonate till it decomposed to form a black residue. The total ma
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Answer:

See below explanation

Explanation:

The correspondent chemical reaction for copper carbonate decomposed by heat is:

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Statement mentions that scientis heated 123.6 g of CuCO₃ (almost a MM), until a black residue is obtained, which weights 79.6 g : this solid residue is formed by CuO, and the remaining mass (approximatelly 44 g) belongs to teh second product, this is, CO₂; as it is a gas compund, it is not certainly included on the solid residue.

So, law of conservation mass is true for this case, since: 123.6 g = 79.6 g + 44 g. As explained, on the solid residue, we don not include the 44 g, which  "escaped" from our system, since it is a gas compound (CO₂)

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3 years ago
In a certain region of space, the electric potential is V(x,y,z)=Axy-Bx^2+Cy , where A,B , and C are positive constants.a) Calcu
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Answer:

a)  Eₓ = - A y + 2B x , b)  Ey = -Ax –C , c) Ez = 0 , d) The correct answer is 3

Explanation:

The electric field and the electric power are related

                    E = - dV / ds

a) Let's find the electric field on the x axis

                  Eₓ = - dV / dx

                  dV / dx = A y - B 2x

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b) calculate the electric field on the y-axis

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                Ey = -Ax –C

c) the electric field on the z axis

              dv / dz = 0

              Ez = 0

.d) at which point the electric field is zero

Since the electric field is a vector quantity all components must be zero

X axis

              0 = = - A y + 2B x

              y = 2B / A x

Axis y

             0 = -Ax –C

              .x = -C / A

We substitute this value in the previous equation

             .y = 2B / A (-C / A)

             .y = 2 B C / A2

The correct answer is 3

6 0
3 years ago
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