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Elan Coil [88]
3 years ago
7

What is the acceleration of a car that increases its velocity from 0 to 100 kilometers per hour in 10 seconds?

Physics
1 answer:
Lunna [17]3 years ago
5 0

Answer:

0.00278 km/sec2 or 36,000 km/hr2 .

Explanation:

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Nitrogen (Z = 7) has three electrons in the 2p level (in addition to two electrons each in the 1s and 2s levels).
solmaris [256]
Based on electrons would be answer b.
8 0
4 years ago
what will be the effect on the acceleration due to gravity of the earth if it is compressed to a the size the moon?​
GuDViN [60]

Answer:

it gravitional pull on earth will increased becauste it is compress to a form of moon which is comperatively smaller so the gravitonal pull on per cm of earth will incrased so we can say that there will be change in acceleration due to gravity

7 0
3 years ago
Read 2 more answers
A rock is projected from the edge of the top of a building with an initial velocity of 12.2 m/s at an angle of 73° above the hor
Brrunno [24]

Answer:

7 s

Explanation:

u = Initial velocity of rock = 12.2 m/s

\theta = Angle of throw = 73^{\circ}

x = Displacement in x direction = 25 m

Displacement in x direction is given by

x=u\cos\theta t\\\Rightarrow t=\dfrac{x}{u\cos\theta}\\\Rightarrow t=\dfrac{25}{12.2\times \cos73^{\circ}}\\\Rightarrow t=7\ \text{s}

Time taken to reach the ground is 7 s.

4 0
3 years ago
Grain is pouring into a silo to be stored for later use. Due to the friction between pieces of grain as they rub against each ot
jolli1 [7]

Answer:

The electric force between them if the pieces of grain are 2 cm apart is 3.15\times 10^{-11}\textrm{ N}.

Explanation:

Given:

Charge on one grain, Q_{1}=6\times 10^{-10}\textrm{ C}

Charge on another grain, Q_{2}=2.3\times 10^{-15}\textrm{ C}

Separation between them, d=2\textrm{ cm}=0.02\textrm{ m}

Electric force acting between two charges Q_{1}\textrm{ and }Q_{2} separated by a distance d is given as:

F_{elec}=\frac{kQ_{1}Q_{2}}{d^2}

Where, k is Coulomb's constant equal to 9\times 10^9\textrm{ }Nm^2/C^2.

Now, plug in all the values and solve for F{elec}.

F{elec}=\frac{9\times 10^9\times 6.0\times 10^{-10}\times 2.3\times 10^{-15}}{(0.02)^2}\\\\F_{elec}=3.15\times 10^{-11}\textrm{ N}

Therefore, the electric force between them if the pieces of grain are 2 cm apart is 3.15\times 10^{-11}\textrm{ N}.

3 0
3 years ago
A solid sphere, solid cylinder, and a hollow pipe all have equal masses and radii. If the three of them are released simultaneou
Roman55 [17]

Answer:

The solid sphere will reach the bottom first.

Explanation:

In order to develop this problem and give it a correct solution, it is necessary to collect the concepts related to energy conservation. To apply this concept, we first highlight the importance of conserving energy so we will match the final and initial energies. Once this value has been obtained, we will concentrate on finding the speed, and solving what is related to the Inertia.

In this way we know that,

\Delta KE = - \Delta PE

KE_t + KE_r = mgh

We know as well that the lineal and angular energy are given by,

KE_r = \frac{1}{2}I\omega^2

And the tangential kinetic energy as

KE_t = \frac{1}{2} mv^2

Where\omega = \frac{v}{R}

Replacing

\frac{1}{2}mv^2 + \frac{1}{2}I\frac{v}{R} = mgh

Re-arrange for v,

v=\sqrt{\frac{2mgh}{m+I/R^2}}

We have here three different objects: solid cylinder, hollow pipe and solid sphere. We need the moment inertia of this objects and replace in the previous equation found, then,

For hollow pipe:

I_{hp}=mR^2

v_{hp}=\sqrt{\frac{2mgh}{m+(mR^2)/R^2}}

v_{hp}=\sqrt{\frac{2mgh}{m+m)}

v_{hp}=\sqrt{gh}

For solid cylinder:

I_{sc}=\frac{1}{2}mR^2

v_{sc}=\sqrt{\frac{2mgh}{m+(1/2mR^2)/R^2}}

v_{sc}=\sqrt{\frac{2mgh}{m+1/2m}}

v_{sc}=\sqrt{\frac{3}{4}gh}

For solid sphere,

I_{ss}=\frac{2}{5}mR^2

v_{ss}=\sqrt{\frac{2mgh}{m+(2/5mR^2)/R^2}}

v_{ss}=\sqrt{\frac{2mgh}{m+2/5m}}

v_{ss}=\sqrt{\frac{10}{7}gh}

Then comparing the speed of the three objects we have:

v_{hp}

\sqrt{gh}

3 0
4 years ago
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