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Elan Coil [88]
3 years ago
7

What is the acceleration of a car that increases its velocity from 0 to 100 kilometers per hour in 10 seconds?

Physics
1 answer:
Lunna [17]3 years ago
5 0

Answer:

0.00278 km/sec2 or 36,000 km/hr2 .

Explanation:

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Which structure reduces friction between joints?
Roman55 [17]

Answer:

The cartilage is the structure that reduces friction between joints.

Explanation:

Cartilage is the tissue between the bone joints. They are composed of several membranes and cellular groups. One of them called synovial membrane which provides lubricant to the edges of tissue that are touched by the bones. Reducing the friction and absorbing it so the body can move without obstacles.

3 0
3 years ago
Where will water evaporate from?
Elodia [21]

Water will evaporate from any water source and life forms. The answer is letter C. An application of heat into water will cause the water to evaporate. This is because the intermolecular forces of attraction of water can be broken by sufficient energy application.

3 0
3 years ago
A conversion factor is a ratio with a value of
Nikitich [7]
The answer would be
B
7 0
3 years ago
what is the power of an electrical device which operates with a current of 12.4 A and a potential difference of 12 V​
jek_recluse [69]

148.8 Watts

Explanation:

P = VI

= (12 V)(12.4 A)

= 148.8 Watts

3 0
3 years ago
A small glass bead has been charged to 20 nC. What is the magnitude of acceleration in m/s^2 of an electron that is 1.0 cm from
MAVERICK [17]

Answer:

The acceleration is 3.16x10¹⁷ m/s².

Explanation:

First, we need to find the magnitude of the Coulombs force (F):

|F| = \frac{Kq_{1}q_{2}}{d^{2}}

<u>Where</u>:

K is the Coulomb constant = 9x10⁹ Nm²/C²

q₁ is the charge = 20x10⁻⁹ C  

q₂ is the electron's charge = -1.6x10⁻¹⁹ C

d is the distance = 1.0 cm = 1.0x10⁻² m

|F| = \frac{Kq_{1}q_{2}}{d^{2}} = \frac{9\cdot 10^{9}Nm^{2}/C^{2}*20 \cdot 10^{-9} C*(-1.6\cdot 10^{-19} C)}{(0.01 m)^{2}} = 2.88 \cdot 10^{-13} N                                      

Now, we can find the acceleration:

a = \frac{F}{m} = \frac{2.88 \cdot 10^{-13} N}{9.1 \cdot 10^{-31} kg} = 3.16 \cdot 10^{17} m/s^{2}

Therefore, the acceleration is 3.16x10¹⁷ m/s².

I hope it helps you!    

7 0
3 years ago
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