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2 years ago

FOR BRAINLIEST! Someone draw me a Rube Goldberg Machine.

Physics

1 answer:

tatyana61 [14]2 years ago

8 0

This ain’t mine but here is someone else’s

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A student pushes a 50-N box across the floor a distance of 15 m. How much work was done to move the box?

irinina [24]

Answer:750

Explanation:

50 times 15

4 0

2 years ago

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A car with an initial velocity of O m/s and a mass of 1500 kg reaches a velocity of 15 m/s in 5

Flura [38]

Answer:the answer can be find out by the following steps;

Explanation:

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3 years ago

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A bullet with a mass of 0.02 kg is fired horizontally into a block of wood hanging on a string. The bullet sricks in the wood an

djyliett [7]

Answer:

u= 20.09 m/s

Explanation:

Given that

m = 0.02 kg

M= 2 kg

h= 0.2 m

Lets take initial speed of bullet = u m/s

The final speed of the system will be zero.

From energy conservation

1/2 m u²+ 0 = 0+ (m+M) g h

m u²=2 (m+M) g h

By putting the values

0.02 x u² = 2 (0.02+2) x 10 x 0.2 ( take g=10 m/s²)

u= 20.09 m/s

7 0

3 years ago

Question 5 of 5<br> What do the arrows in the photograph represent?

tensa zangetsu [6.8K]

BALANCED FORCES

When two forces acting on an object are equal in size but act in opposite directions, we say that they are balanced forces . a stationary object stays still. ... a moving object continues to move at the same speed and in the same direction.

- <em>BRAINLIEST answerer</em>

5 0

2 years ago

This force can either push the block upward at a constant velocity or allow it to slide downward at a constant velocity. The mag

Dmitry [639]

Answer:

Part a)

$F = 135.7 N$

Part b)

$F = 62.5 N$

Explanation:

Part a)

If block is sliding up then net force must be zero and friction will be in opposite to the direction of motion of the block

$Fcos\theta = mg + F_f$

$Fsin\theta = F_n$

so we have

$Fcos\theta = mg + \mu(Fsin\theta)$

$F(cos\theta - \mu sin\theta) = mg$

$F = \frac{mg}{cos\theta - \mu sin\theta}$

$F = \frac{55}{cos50 - 0.310(sin50)}$

$F = 135.7 N$

Part b)

If block is sliding down then net force must be zero and friction will be in opposite to the direction of motion of the block

$Fcos\theta = mg - F_f$

$Fsin\theta = F_n$

so we have

$Fcos\theta = mg - \mu(Fsin\theta)$

$F(cos\theta + \mu sin\theta) = mg$

$F = \frac{mg}{cos\theta + \mu sin\theta}$

$F = \frac{55}{cos50 + 0.310(sin50)}$

$F = 62.5 N$

6 0

3 years ago