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iren2701 [21]
3 years ago
11

Th ph value of milk is close to

Chemistry
1 answer:
slavikrds [6]3 years ago
7 0

Answer:

6.5

Explanation:

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You have 49.8 g of O2 gas in a container with twice the volume as one with CO2 gas. The pressure and temperature of both contain
IrinaVladis [17]

Answer:

34.2 g is the mass of carbon dioxide gas one have in the container.

Explanation:

Moles of O_2:-

Mass = 49.8 g

Molar mass of oxygen gas = 32 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{49.8\ g}{32\ g/mol}

Moles_{O_2}= 1.55625\ mol

Since pressure and volume are constant, we can use the Avogadro's law  as:-

\frac {V_1}{n_1}=\frac {V_2}{n_2}

Given ,  

V₂ is twice the volume of V₁

V₂ = 2V₁

n₁ = ?

n₂ = 1.55625 mol

Using above equation as:

\frac {V_1}{n_1}=\frac {V_2}{n_2}

\frac {V_1}{n_1}=\frac {2\times V_1}{1.55625}

n₁ = 0.778125 moles

Moles of carbon dioxide = 0.778125 moles

Molar mass of CO_2 = 44.0 g/mol

Mass of CO_2 = Moles × Molar mass = 0.778125 × 44.0 g = 34.2 g

<u>34.2 g is the mass of carbon dioxide gas one have in the container.</u>

5 0
3 years ago
235
gizmo_the_mogwai [7]
Huh? . . . . . . . . : )
7 0
3 years ago
Read 2 more answers
The value of the Solubility Product Constant for lead phosphate is ____________
emmasim [6.3K]

<u>Answer:</u> The reaction for the K_{sp} value of lead phosphate is given below and the value of solubility product for the same is 3.0\rightarrow 10^{-44}

<u>Explanation:</u>

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio. It is expressed as K_{sp}

The chemical formula of lead phosphate is Pb_3(PO_4)_2

The equation for the hydration of the lead phosphate is given as:

Pb_3(PO_4)_2(s)+H_2O(l)\rightarrow 3Pb^{2+}(aq.)+2PO_4^{3-}(aq.)

The solubility product of lead phosphate is 3.0\rightarrow 10^{-44}. This means that it is highly insoluble in water as the solubility product is very very low.

Hence, the reaction for the K_{sp} value of lead phosphate is given above and the value of solubility product for the same is 3.0\rightarrow 10^{-44}

4 0
4 years ago
How many grams of sodium chloride are required to prepare 500.0 ml of a 0.100 m solution?
scoray [572]

Answer:

  • <u>2.92 g</u>

Explanation:

<u>1) Data:</u>

a) V = 500.0 ml = 0.500 liter

b) M = 0.100

c) mass = ?

<u>2) Formulae:</u>

a) Molarity: M = n / V

b) Number of moles: n = mass in grams / molar mass

<u>3) Solution</u>

a) M = n / V ⇒ n = M × V = 0.1000 M × 0.500 liter = 0.0500 mol

b) molar mass NaCl = 58.443 g/mol

c) mass = n × molar mass = 0.0500 mol × 58.443 g/mol = 2.92 g

Answer: 2.92 g

4 0
3 years ago
I need help finding arm
navik [9.2K]

Answer:

line 15 is were you can find the a then you look around for the r but as a heads up the m thats supposed to be there was actually inverted into a w in theory it must have been misprinted.

Explanation:

7 0
3 years ago
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