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4 years ago

Could someone please help me with these two questions only ??!!!Thanks a lot!!!!

Mathematics

1 answer:

FrozenT [24]4 years ago

8 0

For number 13, the answer would be C, and for Number 14, the answer would be A.

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Mhanifa can you please help this is due asap

sleet_krkn [62]

Answer:

<h3>Question 1 </h3>

<em>Adjacent angles are supplementary, opposite angles are equal</em>

62 + 5x + 3 = 180
5x = 180 - 65
5x = 115
x = 23

62 = 3y + 2
3y = 60
y = 20

<h3>Question 2</h3>

<em>Diagonals bisect each other</em>

4x = 3x + 7
x = 7

6y = 2y + 16
4y = 16
y = 4

Correct choice is A

6 0

3 years ago

Need help ON THESE TOO PLEASE WILL MARK BRAINLY

LenKa [72]

Answer:

angle 2WZX = angle ZYX ( Since all angles and sides of a rhombus are equal)

ZYX = 2 x 29.5

4x - 10 =90 (since all angles of a rhombus intersect at 90°)

x=90+10/4

x=100/4

x=25

hope this helps

5 0

3 years ago

What explains how to find the quotient of the division<br> -3 1/3 over 4/9

Arturiano [62]

(-3 1/3) / (4/9).....turn -3 1/3 to an improper fraction
(-10/3) / (4/9)...when dividing fractions, flip what u r dividing by, then multiply
-10/3 * 9/4 ...now just multiply
-30/4 or if u need it back as a mixed fraction, it is - 7 1/2

5 0

3 years ago

Find the inverse function of y=(x-2)^2 + 3. please show steps

Lunna [17]

Answer:

$f^{-1}(x)=2\pm\sqrt{x-3}$

Step-by-step explanation:

we have

$y=(x-2)^2+3$

step 1

Exchange the variables (x for y and y for x)

$x=(y-2)^2+3$

Isolate the variable y

step 2

$x=(y-2)^2+3$

subtract 3 both sides

$(y-2)^2=x-3$

step 3

square root both sides

$y-2=\pm\sqrt{x-3}$

step 4

Adds 2 both sides

$y=2\pm\sqrt{x-3}$

step 5

Let

$f^{-1}(x)=y$

$f^{-1}(x)=2\pm\sqrt{x-3}$

8 0

3 years ago

What is the answer for 4(ax+3) 25+3a?

Deffense [45]

100AX + 3A + 300

Step-by-step explanation:

3 0

3 years ago