Question

As a cold front moves through your area The outside temperature drops by 35° F what is the corresponding temperature change in a 80°C and b kelvins

Answer 1

Answer:

The temperature drop in both Centigrade and Kelvin are the same:

$19.44^o\,C$, and $19.44\,K$

Explanation:

Start by converting 35 F and 0 F (the ends of the temp change) into Centigrades using the formula:

$T_C=(F-32)\,\frac{5}{9} \\T_C=(35-32)\,\frac{5}{9}\\T_C=3\,*\frac{5}{9}\\T_C= \frac{15}{9} \,C$

For 0 F:

$T_C=(0-32)\,\frac{5}{9} \\T_C=(-32)\,\frac{5}{9}\\T_C=-32\,*\frac{5}{9}\\T_C= -\frac{160}{9} \,C$

now, the difference of these two values is:

$\frac{15}{9} -(-\frac{160}{9} )=\frac{175}{9} \approx 19.44^o\,C$

Then if the temperature was $80^o C$, then the new temperature is:

$80^o\,C - 19.44 ^o\,C = 60.56^o\,C$

And since the Kelvin scale differences are the same as the differences in the Centigrade scale, the temperature change in Kelvin is of the same magnitude:

$19.44\,K$