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Rus_ich [418]
3 years ago
6

Which best describes how heat energy moves within a system?

Physics
2 answers:
Rzqust [24]3 years ago
8 0
<span>Heat energy is transferred from warmer objects to cooler objects.

</span>
devlian [24]3 years ago
5 0

Answer:

This question is  not complete

Explanation:

There are three ways in which heat is transferred, they are

  • Conduction: Here, heat is transferred from a hot object to a cooler object when both objects come in contact with one another. Here, there must be a contact between the two bodies. This is so because, the particles of the hot objects have a higher kinetic energy than the cooler object, and when they come in contact with the cooler ones, they transfer these energy to the cooler ones. Metals are generally good conductors of heat.
  • Convection: Here, heat is transferred in a liquid or a gas. Hot liquids or gases transfer there heat when they come in contact with cooler ones. There must be contact in this case also. For example, when a kettle of water is boiled, the water at the base of the kettle passes heat energy to the water at the top of the kettle.
  • Radiation: This does not require physical contact but a substance receives heat energy as a result of thermal radiation. For example, the sun produces heat but does not need to touch the metals on earth before they absorb the heat from the sun. So, heat is transferred without a medium or through open space here.
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To test the performance of its tires, a car
velikii [3]

<u>Answer</u>:

The coefficient of  static friction between the tires and the road is 1.987

<u>Explanation</u>:

<u>Given</u>:

Radius of the track, r =  516 m

Tangential Acceleration a_r=  3.89 m/s^2

Speed,v =  32.8 m/s

<u>To Find:</u>

The coefficient of  static friction between the tires and the road = ?

<u>Solution</u>:

The radial Acceleration is given by,

a_{R = \frac{v^2}{r}

a_{R = \frac{(32.8)^2}{516}

a_{R = \frac{(1075.84)}{516}

a_{R = 2.085 m/s^2

Now the total acceleration is

\text{ total acceleration} = \sqrt{\text{(tangential acceleration)}^2 +{\text{(Radial acceleration)}^2

=>= \sqrt{ (a_r)^2+(a_R)^2}

=>\sqrt{ (3.89 )^2+( 2.085)^2}

=>\sqrt{ (15.1321)+(4.347)^2}

=>19.4791 m/s^2

The frictional force on the car will be f = ma------------(1)

And the force due to gravity is W = mg--------------------(2)

Now the coefficient of  static friction is

\mu =\frac{f}{W}

From (1) and (2)

\mu =\frac{ma}{mg}

\mu =\frac{a}{g}

Substituting the values, we get

\mu =\frac{19.4791}{9.8}

\mu =1.987

8 0
3 years ago
The proper IUPAC naming convention for the compound symbol 'KI' is
Darya [45]
Proablyly a or c idk 
6 0
3 years ago
A satellite of mass m is moving in a circular orbit around the earth at a constant speed v and at an altitude h above the earth'
qwelly [4]

The satellite executes a rotation motion around the earth, because Earth's force of attraction plays the role of centripetal force:

Fa=Fcp=>k*Mp*m/(Rp+r)²=mv²/(Rp+r)=>v=√(k*Mp/(Rp+r))=√(6.67*10⁻¹¹*5.98*10²⁴/(6371*10³+1000*10³))=√(39.88*10¹³/(7371*10³))=√(5.41*10⁷)=7355.53 m/s


Check the calculations again !


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3 years ago
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Explanation:

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2 years ago
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When a object is at rest, what is it’s speed??
nadya68 [22]

Answer:

0   (there is no speed)

Explanation:

If an object is at rest, it is not moving, and it doesn't have a speed, so the speed is zero.

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