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Bas_tet [7]
3 years ago
7

A monochromatic light passes through a narrow slit and forms a diffraction pattern on a screen behind the slit. As the wavelengt

h of the light decreases, the diffraction patterna)spreads out with all the fringes getting wider.b)remains unchangedc)spreads out with all the fringes getting alternately wider and then narrower.d)becomes dimmere)shrinks with all the fringes getting narrower.
Physics
1 answer:
azamat3 years ago
8 0

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Mariana [72]

Answer:

1. well the value may vary because of different reactions to the technology because its new to a lot of people but to younger ones its something normal and something we cant live without but with older ones its something that they have lived without for most of there life.

Explanation:

6 0
3 years ago
A certain unbalanced force gives a 5kg object an acceleration of 15 m/s2. What would be the acceleration if the same force was a
stira [4]

Answer:

a2 = 2.5 m/s2

Explanation:

F1 = m1 a1 We use the same force so F1 = F2

= 5kg × 15m/s2 F2 = m2 a2

= 75N a2 is required

a2 = F2 / m2

= 75N / 30 kg

= 2.5 m/s2

7 0
4 years ago
What is the difference between a learner’s license and an operator’s license?
Stells [14]
<span>A Learner’s license is available to those at least 15 years old that have passed the written and vision tests.
</span><span>An intermediate license, you must be 16 or 17 years old and you must have held a learner’s license for at least 12 months without receiving any traffic violations.</span>
5 0
3 years ago
A small metal object is tied to the end of a string and whirled round a circular path of radius 30cm. The object makes 20 oscill
LUCKY_DIMON [66]

Answer:

(i) The angular speed of the small metal object is 25.133 rad/s

(ii) The linear speed of the small metal object is 7.54 m/s.

Explanation:

Given;

radius of the circular path, r = 30 cm = 0.3 m

number of revolutions, n = 20

time of motion, t = 5 s

(i) The angular speed of the small metal object is calculated as;

\omega = \frac{20 \ rev}{5 \ s} \times \frac{2 \pi \ rad}{1 \ rev} = \frac{40\pi \ rad}{5 \ s} = 8\pi \ rad/s = 25.133 \ rad/s

(ii) The linear speed of the small metal object is calculated as;

v = \omega r\\\\v = 25.133 \ rad/s \ \times \ 0.3 \ m\\\\v = 7.54 \ m/s

6 0
3 years ago
When Earth and the Moon are separated by a
Wewaii [24]
     Using the Universal Gratitation Law, we have:

F= \frac{MmG}{d^2}  \\ MmG=2*10^{20}*(3.84*10^8)^2 \\ MmG=29.4912*10^36
 
     Again applying the formula in the new situation, comes:

F= \frac{MmG}{d^2} \\ F= \frac{29.4912*10^36}{(1.92*10^8)^2} \\ \boxed {F=8*10^{20}}

Number 4

If you notice any mistake in my english, please let me know, because i am not native.
6 0
3 years ago
Read 2 more answers
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