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Jlenok [28]
3 years ago
8

I 13 Suggest why this group is called Group 8.​

Chemistry
1 answer:
yarga [219]3 years ago
3 0

Answer:

because it's in group 8

Explanation:

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A chemist weighed out 70.8 g of magnesium. Calculate the number of moles of magnesium she weighed out. Round your answer to sign
solniwko [45]

Answer:

2.91 grams of Magnesium

Explanation:

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What happens after you leave oil and vinegar in a glass for a few minutes?
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An emulsion is formed.

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An association (emulsion) of two liquids is formed, in this case oil and vinegar, which when stirred, said mixture will separate.

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True or False<br> Helium belongs to Noble Metals
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This answer is "True"

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Calculate how many moles of Ca(OH)2 are needed to produce 4.8 x 1024 NH3 molecules, according to the following equation
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3 years ago
The standard enthalpy change for the following reaction is 873 kJ at 298 K.
Flura [38]

Answer:  - 436.5 kJ.

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation.

The given chemical reaction is,

2KCl(s)\rightarrow 2K(s)+Cl_2(g)  \Delta H_1=873kJ

Now we have to determine the value of \Delta H for the following reaction i.e,

K(s)+\frac{1}{2}Cl_2(g)\rightarrow KCl(s) \Delta H_2=?

According to the Hess’s law, if we divide the reaction by half then the \Delta H will also get halved and on reversing the reaction , the sign of enthlapy changes.

So, the value \Delta H_2 for the reaction will be:

\Delta H_2=\frac{1}{2}\times (-873kJ)

\Delta H_2=-436.5kJ

Hence, the value of \Delta H_2 for the reaction is -436.5 kJ.

8 0
3 years ago
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