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Jlenok [28]
3 years ago
8

I 13 Suggest why this group is called Group 8.​

Chemistry
1 answer:
yarga [219]3 years ago
3 0

Answer:

because it's in group 8

Explanation:

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Find the sum of angles x° and y° from the given figure​
tresset_1 [31]

Answer:

where is the figure . u can simply add them

6 0
3 years ago
I need help with number 3. is the answer 1,2,3,or4
lubasha [3.4K]

Answer:

1 and 4

Explanation:

in both pictures the temperature is cooling down

8 0
3 years ago
Be sure to answer all parts.
Fudgin [204]

Answer:

2H₂ + O₂       →     2H₂O

Explanation:

Chemical equation:

H₂ + O₂       →     H₂O

Balance chemical equation:

2H₂ + O₂       →     2H₂O

Step 1:

H₂ + O₂       →     H₂O

Left hand side                     Right hand side

H = 2                                    H = 2

O = 2                                    O = 1

Step 2:

H₂ + O₂       →     2H₂O

Left hand side                     Right hand side

H = 2                                    H = 4

O = 2                                    O = 2

Step 3:

2H₂ + O₂       →     2H₂O

Left hand side                     Right hand side

H = 4                                    H = 4

O = 2                                    O = 2

7 0
3 years ago
PLEASEE ANSWERRR FASTTT
IceJOKER [234]

Answer:

last one

Explanation:

The elements classified as metalloids are boron, silicon, germanium, arsenic, antimony, tellurium, and polonium.

8 0
3 years ago
Read 2 more answers
Compound A is an alkene that was treated with ozone to yield only (CH3CH2CH2)2C=O. Draw the major product that is expected when
DochEvi [55]

Answer:

2,2,3,3-tetrapropyloxirane

Explanation:

In this case, we have to know first the alkene that will react with the peroxyacid. So:

<u>What do we know about the unknown alkene? </u>

We know the product of the ozonolysis reaction (see figure 1). This reaction is an <u>oxidative rupture reaction</u>. Therefore, the double bond will be broken and we have to replace the carbons on each side of the double bond by oxygens. If (CH_3CH_2CH_2)_2C=O is the only product we will have a symmetric molecule in this case 4,5-dipropyloct-4-ene.

<u>What is the product with the peroxyacid?</u>

This compound in the presence of alkenes will produce <u>peroxides.</u> Therefore we have to put a peroxide group in the carbons where the double bond was placed. So, we will have as product <u>2,2,3,3-tetrapropyloxirane.</u> (see figure 2)

3 0
3 years ago
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