Efficiency is the estimation of output power by any machine. A 12% efficient engine has an output provided by the input energy of the engine. Thus, option D is correct.
<h3>What is efficiency?</h3>
Efficiency is defined as the energy given by the machine, engine, or any system by utilizing the input power or energy. It is given as,
η = Output ÷ Input × 100%
It is used to know the ability of the machine to transfer the input energy to an external amount of work. The engine with 12% efficiency is said to have produced energy by utilizing the provided 12% input.
Therefore, option D. the 12% of input power is used by the engine to produce the energy.
Learn more about efficiency here:
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Answer:
a.
![K=\frac{[BaO]^2}{[Ba]^2[O_2]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BBaO%5D%5E2%7D%7B%5BBa%5D%5E2%5BO_2%5D%7D)
b.
![K=\frac{[MgO]^2}{[Mg]^2[O_2]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BMgO%5D%5E2%7D%7B%5BMg%5D%5E2%5BO_2%5D%7D)
c.
![K=\frac{[P_4O_{10}]^2}{[P_4][O_2]^5}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BP_4O_%7B10%7D%5D%5E2%7D%7B%5BP_4%5D%5BO_2%5D%5E5%7D)
Explanation:
Hello!
In this case, since the equilibrium expression is set up by dividing the products over the reactants and powering to the stoichiometric coefficient, we can proceed as follows:
a. 2 Ba + O2 ⇌ 2 BaO.
b. 2 Mg + O2 ⇌ 2MgO
c. P4 + 5 O2 ⇌ P4O10
Best regards.
34g
Considering total mass as100g
I am sorry if it’s wrong
Answer:
If you constructed graphs, what trends do they indicate in your data?
