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4 years ago

Which process has led to the production of most modern domesticated crops and livestock

Physics

2 answers:

Nesterboy [21]4 years ago

8 0

The Answer is A: Selective Breeding.

boyakko [2]4 years ago

6 0

A selective breeding. Put your best animals together to get better offspring.

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A group of physics students hypothesize that for an experiment they are performing, the speed of an object sliding down an incli

goblinko [34]

Answer:

v = 2.974

Explanation:

Perhaps the formula should be

v = √(2*g*d (sin(θ) - uk*cos(θ) ) This is a bit easier to read.

v = √(2* 9.80*0.725(0.707 - 0.12*0.707) ) Substitute values. Find 2*g*d

v = √14.21 * (0.707 - 0.0849) Figure out Sin(θ) - uk cos(θ)

v = √14.21 * (0.6222)

v = √8.8422 Take the square root of the value

v = 2.974

6 0

4 years ago

Read 2 more answers

After a projectile is fired into the air, what is the acceleration in the x-direction? (Assume no air resistance.)

Gre4nikov [31]

Without air resistance, there is no horizontal force on the projectile,
so it has no horizontal acceleration. The answer is "zero".

4 0

3 years ago

Read 2 more answers

Question 10 of 10 Closure is the process of:

pshichka [43]

Answer:

Closure is the process of: Closing

Explanation:

Please visit my church's website at fbcinterlaken.org to learn more about God. Please subscribe to the You Tube channel because my church really needs the support right now. Thank you! And have a nice day! :) (I will take brainliest).

3 0

3 years ago

if the vessel in the sample problem accelerates fir 1.00 min, what will its speed be after that minute ?

LUCKY_DIMON [66]

Answers:

a) 154.08 m/s=554.68 km/h

b) 108 m/s=388.8 km/h

Explanation:

The complete question is written below:

In 1977 off the coast of Australia, the fastest speed by a vessel on the water was achieved. If this vessel were to undergo an average acceleration of $1.80 m/s^{2}$ , it would go from rest to its top speed in 85.6 s.

a) What was the speed of the vessel?

b) If the vessel in the sample problem accelerates for 1.00 min, what will its speed be after that minute?

Calculate the answers in both meters per second and kilometers per hour

a) The average acceleration $a_{av}$ is expressed as:

$a_{av}=\frac{\Delta V}{\Delta t}=\frac{V-V_{o}}{\Delta t}$ (1)

Where:

$a_{av}=1.80 m/s^{2}$

$\Delta V$ is the variation of velocity in a given time $\Delta t$ , which is the difference between the final velocity $V$ and the initial velocity $V_{o}=0$ (because it starts from rest).

$\Delta t=85.6 s$

Isolating $V$ from (1):

$V=a_{av}\Delta t + V_{o}$ (2)

$V=(1.80 m/s^{2})(85.6 s) + 0 m/s$ (3)

$V=154.08 \frac{m}{s}$ (4)

If $1 km=1000m$ and $1 h=3600 s$ then:

$V=154.08 \frac{m}{s}=554.68 \frac{km}{h}$ (4)

b) Now we need to find the final velocity when $\Delta t=1 min=60 s$ :

$V=(1.80 m/s^{2})(60 s) + 0 m/s$ (5)

$V=108 \frac{m}{s}=388.8 \frac{km}{h}$ (6)

5 0

3 years ago

A hot air balloon rises at a constant speed of 13 meters/second relative to the air. There is a wind blowing eastwards at a spee

Airida [17]

Answer:

13.02 m/s the velocity and 86.92 degrees the direction relative to ground

Explanation:

We need to add velocities in vector addition to find the resultant velocity " $v$ " of the balloon (the 13 m/s and the 0.7 m/s).

The velocities are at 90 degrees from each other (one pointing up and the other to the East). Notice from the attached image that the resultant velocity vector (picture in red) is actually the hypotenuse of a right angle triangle.

So we use Pythagoras to find the length (magnitude) of the resultant velocity vector:

$v = \sqrt{13^2 +0.7^2} = 13.018832...$

we can round the answer to 13.02 m/s

Now we need to find the angle that this new vector makes with the ground by using the definition of tangent of an angle that relates the two quantities that we just added:

$tan (\theta) = 13/0.7 \\ \theta = arctan (\frac{13}{07} = 86.91781918...$

So we round it to 86.92 degrees

5 0

3 years ago