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sveticcg [70]
3 years ago
9

A vehicle with a mass of 2,553 kg accelerates at 10 m/s2. Find the force on the vehicle in Newtons.​

Physics
1 answer:
Lerok [7]3 years ago
8 0

Answer:

F = 25530 N

Explanation:

F(net) = ma

F(net) = 2553 kg•(10) m/s² = 25530 N

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A 350-g baseball is shot out of a small cannon with a velocity of 9.0 m/s. The baseball flies horizontally at a constant height
stira [4]

Answer:

9.5 kg m^2/s

Explanation:

The angular momentum of an object is given by:

L=mvr

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v is its velocity

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Here we have:

m = 350 g = 0.35 kg is the mass of the ball

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L=(0.35)(9.0)(3.0)=9.5 kg m^2/s

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4 years ago
True or False:
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A 25,000 kg traveling east collides with a 2,000 kg truck standing still on the tracks. After the collision the train and truck
Elis [28]

Answer:

24.084 m/s

Explanation:

From the law of conservation of linear momentum

Total momentum before collision equals to the total momentum after collision

Since momentum=mv where m is mass and v is velocity

M_{truck}V_{truck}=V_{common}*(M_{truck} +M_{standing}) where M_{truck} is the mass of the truck, V_{truck} is velocity of the truck, V_{common} is the common velocity of moving and standing truck after collision and M_{standing} is the mass of the standing truck

Making V_{truck} the subject we obtain

V_{truck}=\frac { V_{common}*(M_{truck} +M_{standing})}{M_{truck}}

Substituting M_{truck} as 25000 Kg, V_{common} as 22.3 m/s, M_{standing} as 2000 Kg we obtain

V_{truck}=\frac { 22.3 m/s *(25000 Kg +2000 Kg)}{25000}= 24.084 m/s

Therefore, assuming no friction and considering that after collision they still move eastwards hence common velocity and initial truck velocities are positive

The truck was moving at 24.084 m/s

3 0
3 years ago
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