Technician A says that when the MIL is on, the technician should retrieve the DTC and follow the manufacturer's recommended proc
1 answer:
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Answer:
T₂ = 305.17 K
Explanation:
Given that,
Heat, Q = 6000 J
Mass, m = 200 gram
Initial temperature, T₁ = 25° C
We need to find its final temperature. Let it is T₂.
We know that,
Where
c is the specific heat of water, c = 4.18 J/g°C
So,
So, the final temperature is equal to 305.17 K.
Answer:
C.)Finding the area bound by the horizontal axis and the curve from 0 s to 5 s
D.)Using Average Speed = total distance/total and multiplying the average speed of 5m/s by a total time of 5 s
Explanation:
The graph seems to be missing, however we can still answer the question.
In fact, we have to keep in mind the following facts:
- In a velocity-time graph, the area under the curve represents the displacement of the object, while the slope of the curve corresponds to its acceleration.
From this, we can already say that the following option:
C.)Finding the area bound by the horizontal axis and the curve from 0 s to 5 s
is correct, while the statement
A.)Finding the slope of the line between 0 s to 5 s
is wrong.
Moreover, the average speed of an object in motion is given by
where d is the total distance covered while t is the total time taken. Once we have calculated the average speed, the total displacement over a certain time period can be simply calculated by multiplying the average speed by the time interval: so, the option
D.)Using Average Speed = total distance/total and multiplying the average speed of 5m/s by a total time of 5 s
is also correct.
The last option remained:
B.)Dividing the change in velocity between 0 s to 5 s by the change in time
is wrong, because in this way we are calculating the acceleration, not the displacement.