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mamaluj [8]
3 years ago
5

Technician A says that when the MIL is on, the technician should retrieve the DTC and follow the manufacturer's recommended proc

edure to find the root cause of the problem. Technician B says that all OBD II monitors must have the enable criteria achieved before a test is performed. Who is right?
A) Technician A
B) Technician B
C) Both technicians
D) Neither technician
Physics
1 answer:
evablogger [386]3 years ago
7 0

Answer:

i think its both A and ab

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A 40-turn coil has a diameter of 11 cm. The coil is placed in a spatially uniform magnetic field of magnitude 0.40 T so that the
seropon [69]

Answer:

(a) emf = 0.507 V

(b) emf = 0.0507 V

(c) emf = 0.00234 V

Explanation:

Given;

number of turns of the coil, N = 40 turns

diameter of the coil, d = 11 cm

radius of the coil, r = 5.5 cm = 0.055 m

magnitude of the magnetic field, B = 0.4 T

The magnitude of the induced emf is calculated as;

emf = - N\frac{d\phi}{dt} \\\\where;\\\\\phi \ is \ magnetic \ flux= BA \\\\A \ is the \ area \ of \ the \ coil = \pi r^2 = \pi (0.055)^2 = 0.0095 \ m^2\\\\emf = - N \frac{dB.A}{dt} = -NA\frac{dB}{dt} \\\\emf = -NA\frac{(B_2 - B_1)}{t} \\\\emf = NA \frac{(B_1 - B_2)}{t} \\\\the \ final \ magnetic \ field \ is \ reduced \ to \ zero;\ B_2 = 0\\\\emf = \frac{NAB_1}{t}

(a) when the time, t = 0.3 s

emf = \frac{NAB_1}{t} = \frac{40\times 0.0095\times 0.4}{0.3} = 0.507 \ V

(b) when the time, t = 3.0 s

emf = \frac{NAB_1}{t} = \frac{40\times 0.0095\times 0.4}{3} = 0.0507 \ V

(c) when the time, t = 65 s

emf = \frac{NAB_1}{t} = \frac{40\times 0.0095\times 0.4}{65} = 0.00234 \ V

7 0
3 years ago
If a car has a mass of 200 kg and produces a force of 500 N how fast was the car accelerate
Crank

Answer:

2.5

Explanation:

force/weight

5 0
4 years ago
Read 2 more answers
The mysterious visitor that appears in the enchanting story The Little Prince was said to come from a planet that "was scarcely
FromTheMoon [43]

Answer:

Part a)

g = 1 \times 10^{-5} m/s^2

Part b)

v = 0.011 m/s

Explanation:

Part a)

As we know that the acceleration due to gravity is given as

g = \frac{GM}{R^2}

g = \frac{G(\frac{4}{3}\pi R^3 \rho)}{R^2}

g = \frac{4}{3}\pi \rho G R

now we know that

\rho = \frac{M}{\frac{4}{3}\pi R^3}

\rho = \frac{5.98 \times 10^{24}}{\frac{4}{3}\pi (6.37 \times 10^6)^3}

\rho = 5523.2 kg/m^3

now we have

g = \frac{4}{3}\pi (5523.2) (6.67 \times 10^{-11})(6.5)

g = 1 \times 10^{-5} m/s^2

Part b)

As we know that the escape speed is given as

v = \sqrt{\frac{2GM}{R}}

v = \sqrt{2gR}

v = \sqrt{2(1\times 10^{-5})(6.5)}

v = 0.011 m/s

8 0
3 years ago
Ryan is playing with a ball. When would the ball<br> have the greatest polential energy?
forsale [732]
When the ball is not moving
7 0
4 years ago
An apple falls straight down from a tree and hits the ground in approximately 0.75 seconds. Based on this information, which is
Mnenie [13.5K]

Answer:

y = 2.76 [m]

Explanation:

We can find the distance of the fall of the apple using the following kinematic equation, we have to emphasize that this is a typical problem of free fall, so the initial speed is zero, then we give the initial data.

t = time = 0,75[s]

g = gravity = 9.81[m/s^2]

v0 = 0

y = v_{0}*t+0.5*g*t^{2}\\ y=0.5*(9.81)*(0.75)^{2}\\y= 2.76[m]

3 0
4 years ago
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