Answer:505.94 N
Explanation:
Given
mass of child (m)=41 kg
N=60 rpm
Radius(r)=1.25 m
and centripetal acceleration is given by 
Answer:
Let us develop the transformation of force from a system S where a particle is moving at a speed v to any system S' which is moving relative to system S at a speed V. ...
Explanation:
hope it works out
According to newton's 3rd law of motion,
For every action, there is equal and opposite reaction. So if we move a body against a rough surface, there were be reaction against the force applied.
So using conservation of energy, we know:
Work done to move a body = Work done against Friction
So, Force applied * distance moved = coefficient of Friction * Normal Reaction * distance moved
For a body moving against a normal surface, Normal Reaction (R) = mg
or, mass * acceleration * distance (s) = ∪ * R * distance(s)
or, mass * (v^2/2s) = ∪ * mass * gravity
Now, s = stopping distance = v²/ 2∪g
so, using given value,∪=0.05,
s = v2/2*0.05*g
We know, g = 10, so s = v²/(2*0.05*10) = v²
where v = initial velocity
