What is the word that means "these break food into pieces

I need help with empirical formula calculations

AysviL [449]

Answer:

I think it’s onlineeeeeee

Explanation:

7 0

3 years ago

Read 2 more answers

Which level of organization refers to all the types of environments in which organisms can be found?

NeX [460]

B , Biosphere is a special shell of the Earth inhabited by living organisms

8 0

4 years ago

Mr. Keith lights a pine tree-scented candle in his office before grading his students’ CRQs. While the candle wick burns, some o

ANEK [815]

Answer:

the answer is w

Explanation:

4 0

4 years ago

During the reaction, 3.40 μmolμmol of HClHCl are produced. Calculate the final pHpH of the reaction solution. Assume that the HC

Bezzdna [24]

Answer:

Final pH of the solution = 5.46

Explanation:

The detailed step is shown in the attachment.

6 0

3 years ago

A compound that contains only carbon, hydrogen, and oxygen is 58.8% C and 9.87% H by mass. What is the empirical formula of this

Dmitry [639]

Answer: The empirical formula of the compound becomes $C_5H_{10}O_2$

Explanation:

The empirical formula is the chemical formula of the simplest ratio of the number of atoms of each element present in a compound.

Let the mass of the compound be 100 g

Given values:

% of C = 58.8%

% of H = 9.87%

% of O = [100 - 58.8 - 9.87] = 31.33%

Mass of C = 58.8 g

Mass of H = 9.87 g

Mass of O = 31.33 g

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Molar mass of C = 12 g/mol

Molar mass of H = 1 g/mol

Molar mass of O = 16 g/mol

Putting values in equation 1, we get:

$\text{Moles of C}=\frac{58.8g}{12g/mol}=4.9 mol$

$\text{Moles of H}=\frac{9.87g}{1g/mol}=9.87 mol$

$\text{Moles of O}=\frac{31.33g}{16g/mol}=1.96mol$

Step 2: Calculating the mole ratio of the given elements.

Calculating the mole fraction of each element by dividing the calculated moles by the least calculated number of moles that is 1.96 moles

$\text{Mole fraction of C}=\frac{4.9}{1.96}=2.5$

$\text{Mole fraction of H}=\frac{9.87}{1.96}=5.03\approx 5$

$\text{Mole fraction of O}=\frac{1.96}{1.96}=1$

Converting the mole fraction into whole numbers by multiplying them with 2.

$\text{Mole fraction of C}=2.5\times 2=5$

$\text{Mole fraction of H}=5\times 2=10$

$\text{Mole fraction of O}=1\times 2=2$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 5 : 10 : 2

Hence, the empirical formula of the compound becomes $C_5H_{10}O_2$

8 0

3 years ago