Using the ideal gas law PV =nRTPV=nRT , we find that the pressure will be P =\frac{nRT}{V}P=
V
nRT
. Then, we'll substitute and find the pressure, using T = -25 °C = 248.15 K and R = 0.0821 \frac{atm\cdot L}{mol \cdot K}
mol⋅K
atm⋅L
:
P =\frac{nRT}{V} = \frac{(0.33\,\cancel{mol})(0.0821\frac{atm\cdot \cancel{L}}{\cancel{mol \cdot K}})(248.15\,\cancel{K})}{15.0\,\cancel{L}} = 0.4482\,atmP=
V
nRT
=
15.0
L
(0.33
mol
)(0.0821
mol⋅K
atm⋅
L
)(248.15
K
)
=0.4482atm
In conclusion, the pressure of this gas is P=0.4482 atm.
Reference:
Chang, R. (2010). Chemistry. McGraw-Hill, New York.
30.4 is the answer
<span> composition is: 58.8 0/0 C, 9.9 0/0 H, and 31.3 0/0 </span>O<span>. Ifit's molecular mass is 306 ... composition of the </span>compound<span> is </span>30.4<span>% </span>
Gold is known to be an element. The term that best describes 10-karat gold is that it is an homogeneous mixture.
- Gold as an element of often has an ideal state of purity where there contains nothing but gold atoms.
A heterogeneous mixture is known to be a mixture that cannot be chemically sound everytime. Gold jewelry is known to be a homogeneous mixture as it is always will look good and remain unchanged for a long time.
As good example of homogeneous products, e.g a 1-kilogram 24-karat gold bar has unique properties.
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Subtractive colors mixing with all three primaries will result in black.
<h3>How are the 3 primary subtractive colors combined?</h3>
Adding all three subtractive primary color filters together will absorb all the colors of the white light spectrum as appeared below. Each filter (or pigment) absorbs its harmonizing color and transmits (diffusely reflects) the others.
Primary colors union of these three results in white. The subtractive primary colors are related to the subtraction of light: cyan, magenta, and yellow, the colors used in four-color printing, the union of these results in black.
So we can conclude that the usually used subtractive primary colors are cyan, magenta, and yellow, and if you overlap all three in a successful equal mixture.
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The rate of reaction refers to how fast or slow a reaction is. The rate of reaction can be increased by;
i) Using finely divided sodium carbonate
ii) Increasing the temperature
<h3>Rate of reaction</h3>
Thee term rate of reaction refers to the pace of a chemical reaction. A reaction could be fast or slow.
To increase the rate of this reaction;
i) The sodium bicarbonate could be used in the finely divided form.
ii) The temperature could be raised.
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