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sergey [27]
3 years ago
8

What is the molarity of a solution of 14.0 g NH4Br in enough H20 to make 150 mL of solution?

Chemistry
1 answer:
timofeeve [1]3 years ago
7 0
First, calculate the molar mass of NH4Br, which is 97.943 g/mol. By dividing 14 by the molar mass, you find that in the sample, there are <span>0.1429 moles of NH4Br. Next, You divide the number of moles of NH4Br by the liters of the solvent (H20). This is a 0.9529 M solution.</span>
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To solve this question we must find the molar mass of ammonium carbonate. With the molar mass and the mass we can find its moles, as follows:

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Molar mass: 28.0 + 8.0 + 12.0 + 48.0 = 96.0g/mol

The moles of ammonium carbonate in 35.8g are:

35.8g * (1mol / 96.0g) =

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