Answer:
12 possibilities
Step-by-step explanation:
In the first urn, we have 4 balls, and all of them are different, as they have different labels, so the group of two red balls r1 and r2 is different from the group of red balls r2 and r3.
The same thing occurs in the second urn, as all balls have different labels.
The problem is a combination problem (the group r1 and r2 is the same group r2 and r1).
For the first urn, we have a combination of 4 choose 2:
C(4,2) = 4!/2!*2! = 4*3*2/2*2 = 2*3 = 6 possibilities
For the second urn, we also have a combination of 4 choose 2, so 6 possibilities.
In total we have 6 + 6 = 12 possibilities.
Answer:
Part a) 
Part b) 
Part c) 
Part d) 
Step-by-step explanation:
see the attached figure to better understand the question
we know that
To find the length of the image after a dilation, multiply the length of the pre-image by the scale factor
Part a) we have
The scale factor is 5
The length of the pre-image is 3 cm
therefore
The length of the image AB after dilation is

Part b) we have
The scale factor is 3.7
The length of the pre-image is 3 cm
therefore
The length of the image AB after dilation is

Part c) we have
The scale factor is 1/5
The length of the pre-image is 3 cm
therefore
The length of the image AB after dilation is

Part d) we have
The scale factor is s
The length of the pre-image is 3 cm
therefore
The length of the image AB after dilation is

We are seeing 30, 60, 90, triangles, and 45, 45, 90, triangles.
13. 3 root 3
14. 5 root 2
15. 7/2 root 2
16. 3/2 root 2
17. 7.5 root 3
19. bc is squared root 37
20. 32 + 32 root 3