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3 years ago

How do I identify significant figures in chemistry?

1 answer:

3 0

1) START counting for sig. figs. On the FIRST non-zero digit.

2) STOP counting for sig. figs. On the LAST non-zero digit.

3) Non-zero digits are ALWAYS significant.

4) Zeroes in between two non-zero digits are significant. All other zeroes are insignificant.

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Consider the reaction represented by the equation?2SO2(g) + O2(g) 2SO3(g).?For the system at chemical equilibrium, which of the

rewona [7]

Answer:

b. The amount of SO3(g) decreases and the value for K increases.

Explanation:

Hello,

In this case, for the given reaction:

$2SO_2(g) + O_2(g)\rightleftharpoons 2SO_3(g)$

The change in the stoichiometric coefficient is:

$\Delta \nu=2-2-1=-1$

In such a way, since the reagents have more moles than the products, based on Le Chatelier's principle, if the volume is increased, the side with more moles is favored. In addition, since the formation of reagent is favored, K is diminished based on the law of mass action shown below:

$K=\frac{[SO_3]_{eq}^2}{[SO_2]_{eq}^2[O_2]_{eq}}$

Therefore the answer is:

b. The amount of SO3(g) decreases and the value for K increases.

Best regards.

3 0

4 years ago

"30 mph north" is an example of:<br> O velocity<br> speed<br> distance<br> O displacement

Dmitrij [34]

Answer:

distance velocity displacement, all three

Explanation:

7 0

3 years ago

Calculate how much Kool-aid you will need to make 0.5 L of each of the following solutions: 0.1M, 0.4M, & 0.7M.

icang [17]

Answer:

the 4th option

Explanation:

because i said so

8 0

3 years ago

I need help on #2 a and b. please explain steps and answer

Vaselesa [24]

I think A. o2 is oxygen, h202 is a clear liquid like bleach, And H20 is water lol :P

4 0

3 years ago

How do you calculate the number of photons having a wavelength of 10.0 micrometers required to produce 1.0 kilojoules of energy

shtirl [24]

To calculate this,

We know that energy is 1 photon
E = hc/wavelenth
wavelength of 10.0 m

Solution:
h = 6.626 x 10^-34 Jsec
C = 2.9979 x 10^8 m/sec
E = 6.626 10^-34 * 2.9979 10^8 / 10 = 1.9864 10^-26J

Then, the number of photons is computed by:

n = 1000 / 1.9864 10^-26 = 5.04 10^28 photons

4 0

3 years ago