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Mariana [72]
3 years ago
15

Which of an atom's electrons are inrolved in chemical reactions?

Chemistry
2 answers:
Scrat [10]3 years ago
8 0

Answer:

Electrons at the outermost energy level of an atom are called valence electrons. They determine many of the properties of an element. That's because these electrons are involved in chemical reactions with other atoms. Shared electrons bind atoms together to form chemical compounds.

Explanation:

Sophie [7]3 years ago
3 0

Answer:

electrons farthest from the nucleus of the atom. they are called valence electrons

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PLEASE HELP...............................................
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Umm its not a i think... lemme see lol

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4 years ago
Determine the empirical formula. a 3.880g sample contains 0.691g of magnesium , 1.84 g of sulfur , and 1.365 g of oxygen .
Aliun [14]

Answer:

Mg S2 O3

Explanation:

.691 g of Mg  is .284 mole

1.84 g of S    is .5739 mole

1.365 g of O is  .8531 mole      you can see the ratio is ~  1 :2 :3

                                                        Mg S2 O3

4 0
2 years ago
What does the pacific tsunami warning system use to detect tsunamis ?
S_A_V [24]

Answer:

C

Explanation:

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7 0
3 years ago
A sample containing 2.30 mol of Ne gas has an initial volume of 8.00 L. What is the final volume, in liters, when the following
marta [7]

Answer:

a. 4,00L

b. 16,00L

c. 12,31L

Explanation:

Avogadro's law says:

\frac{V_1}{n_1} =\frac{V_2}{n_2}

a. If initial conditions are 2,30mol and 8,00L and you lose one-half of atoms, that means you have 1,15mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{1,15mol}

<em>V₂ = 4,00L</em>

b. If initial conditions are 2,30mol and 8,00L and you add 2,30mol, that means you have 4,60mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{4,60mol}

<em>V₂ = 16,00L</em>

c. 25,0g of Ne are:

25,0g × (1mol / 20,1797g) = 1,24 moles of Ne. That means you have 2,30mol - 1,24mol = 3,54mol of Ne

\frac{8,00L}{2,30mol} =\frac{V_2}{3,54mol}

<em>V₂ = 12,31L</em>

I hope it helps!

6 0
4 years ago
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