When a liquid or a gas is heated, it expands and becomes less dense, so it rises, while the cooler, denser liquid or gas sinks. (Not sure if this helps but this is what I hit)
Answer:
Are you looking for the formula? because if so:
M L^2 T^-3 I^-2
Explanation:
May I have brainliest please? :)
Answer:
L = 0.48 H
Explanation:
let L be the inductance, Irms be the rms current, Vrms be the rms voltage and Vmax be the maximum voltage and XL be the be the reactance of the inductor.
Vrms = Vmax/(√2)
= (3.00)/(√2)
= 2.121 V
then:
XL = Vrms/I
= (2.121)/(2.50×10^-3)
= 848.528 V/A
that is L = XL/(2×π×f)
= (848.528)/(2×π×(280))
= 0.482 H
Therefore, the inductance needed to kepp the rms current less than 2.50mA is 0.482 H.
Answer:
x = 0.81 m
Explanation:
given,
spring constant, k = 769 N/m
Potential energy of the spring = 250 J
distance of spring compression = ?
using conservation of energy
potential energy will equal to the spring energy


x² = 0.650
x = 0.81 m
Hence, the spring is compressed to 0.81 m