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rodikova [14]
3 years ago
15

Is this the correct answer?

Chemistry
1 answer:
Alona [7]3 years ago
8 0
I believe so, looks like it
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Which of these is an acid. PLSSS I NEED DIS NOW!
nlexa [21]
The answer would be A) vinegar. Vinegar is an acid.
Hope this helps!
5 0
3 years ago
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What information is given in a chemical formula?
vovikov84 [41]
The type of atoms present in the chemical compound and the proportion or how many specific atoms are respect to other atoms in the chemical compound.
7 0
3 years ago
Can you please help solve and explain the steps for the calculation?
Nimfa-mama [501]

Answer:

The hydrogen ion concentration in a solution, [H+], in mol L-1, can be calculated if the pH of the solution is known.

pH is defined as the negative logarithm (to base 10) of the hydrogen ion concentration in mol L-1 pH = -log10[H+] ...

[H+] in mol L-1 can be calculated using the equation (formula): [H+] = 10-pH

8 0
2 years ago
g, Assuming the precipitate is totally insoluble in water, which aqueous ions will be present in the solution (collected in the
Allushta [10]

Answer:

Cl⁻, Na⁺, OH⁻

Explanation:

The titration is:

CuCl₂(aq) + 2 NaOH(aq) → Cu(OH)₂(s) + 2 NaCl(aq)

In solution, before the reaction, the ions are Cu²⁺ and Cl⁻. The addition of NaOH (Na⁺ + OH⁻) produce the precipitation of Cu²⁺ forming Cu(OH)₂(s). When you reach the equivalence point, there is no Cu²⁺ because precipitates completely. All OH⁻ ions reacts when are added but when Cu²⁺ is finished, excess OH⁻ ions still in solution helping to detect the equivalence point.

Thus, ions present after the equivalence point are:<em> Cl⁻, Na⁺</em> (Don't react, spectator ions), and <em>OH⁻</em>.

3 0
3 years ago
How many atoms are in 1.15 mole Cu?
xxMikexx [17]
6.022x10^23 is Avogadro’s number. Use this whenever you work with Stoichiometry involving Atoms, formula units, or molecules. 1 mol of anything is always Avogadro’s number.

Multiply everything on the top= 6.93 x 10^23
Divide by everything on the bottom = 6.93 x 10^23
Answer: 6.93 x 10^23 atoms Cu.

4 0
3 years ago
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